4. A solution of malonic acid, H,CH,04, was standardized by titration with 0.1000 M NaOH solution….
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Question “4. A solution of malonic acid, H,CH,04, was standardized by titration with 0.1000 M NaOH solution….”
4. A solution of malonic acid, H,CH,04, was standardized by titration with 0.1000 M NaOH solution. If 20.76 mL of the NaOH solution is required to neutralize completely 12.95 mL of the malonic acid solu- tion, what is the molarity of the malonic acid solution? H,CH,O4 +2NaOH- Na C3H,04 +2H,0
Answer
Balanced equation: H.CH.04+ 2NaOH- Na2CH.04 +2H.0 Number of moles NaOH = 0.1000x 20.76mLX- 1000mL= 0.002076 mole Needed moles of H.C.H.O =0.002076mole NaOH — Mole H.CH.04 2mole NaOH =0.001038mole H.C.H.04. L Volume of solution=12.95mL X 1000mL = 0.0295 L 0.001038mole Concentration H,CH.O4 =-0.01295L =0.08015mole H,C.H.04.
Conclusion
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