A compound has the ‘H NMR spectrum shown below. Identify the compound. 11 10 9 00…
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Question “A compound has the ‘H NMR spectrum shown below. Identify the compound. 11 10 9 00…”
Answer
Top – First spectra
Answer:
Explanation: NMR peaks in aromatic regions in the given option, while other options will also have their peak in aliphatic regions.
Second spectra starting at the top
Answer:
Explanation: In the aliphatic area, two triplets and one mutiplet are due to the n-propyl groups and peak at the aromatic region is due phenyl-group terefoe NMR spectrum is belong to n–propylbenzene
Third spectra starting at the top
Answer: CH3CN
Explaination: The electron withdrawing nature CN group causes the peak to be slightly downfielded. For benzene CHCl3, CHCl2, will have a singlet peak that is more downfielded. For cyclohexane, we will have an upfielded peak. Therefore, CH3CN is the answer.
Fourth and fifth spectra are available from the top
Answer:
Explaination: The two triplets and one mutiplet are due to the n-propyl groups. The triplet peak at 3.5ppm is due methylene attached to oxygen
The singlet is around 2.1 ppm due to the hydroxy group
Therefore, NMR belongs to n-propanol
Conclusion
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