**A cylindrical copper cable 1.90km long is connected across a 220.0V -potential difference. What should be its…**

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## Question “A cylindrical copper cable 1.90km long is connected across a 220.0V -potential difference. What should be its…”

A cylindrical copper cable 1.90km long is connected across a

220.0V -potential difference.

What should be its diameter so that

it produces heat at a rate of 70.0W ?

What is the

electric field inside the cable under these conditions?

## Answer

To solve the question, you will need to know power rule, Ohms law, the relation between resistance and wire diameter, and the relation between electric field and electric potential.

Find the relationship between power, voltage, and resistance. The above equation will allow you to calculate the resistance of your wire. The radius of the wire is calculated from the expression for resistance. The diameter of the wire is calculated by multiplying it with 2. The electric field within the wire can be found by using the relationship between the electric potential, the length of the wire and the electric field. The electric field can thus be calculated.

Ohm’s law describes the relationship between voltage, current and resistance. According to this law, the electric current is proportional to voltage and ininverse proportion to resistance.

The law of Ohm allows for expression by

denotes the voltage, #media_tag_2$ the current and @media_tag_3$ the resistance.

The flow of electric charge is called electric current. The resistance to electric current is called electrical resistance. The electrical potential difference between two points is called voltage.

Resistance to wire is provided by

determines the length and

the area.

The “rate at which you do work per unit of time” is power. The math expression for power rule can be found at,

represents the power lost, @media_tag_11$ the current, and @media_tag_12$ the voltage.

The “negative gradient” of scalar potencial is what we call electric field. Scalar potential refers to the “Amount work required to move a small charge from zero to some point”. Potential difference refers to the difference in potential between two points.

The expression for the electric field between plates is:

represents the electric field between the plates.

indicates the potential difference and #media_tag_16$ the distance.

The power to rule is granted by

In the expression above, substitute

with *I*.

Resistance to the wire is

Substitute HTMLmedia_tag_21$ to HTMLmedia_tag_22$ or HTMLmedia_tag_23$ to

.

Take into account the expression resistance of the wire.

The wire’s area is

Substitute

to

,

to

and

to

.

Take into account the expression “area of the wire”.

Radius of the wire

Substitute HTMLmedia_tag_37$ to

or HTMLmedia_tag_39$ to

.

The diameter of the wire is

.

The cable contains an electric field.

The distance can also be taken to mean the length of the wire. The expression above can be written as follows:

Substitute HTMLmedia_tag_48$ to

or HTMLmedia_tag_50$ to

.

Ans:

.

The electric field within the cable is

.

## Conclusion

Above is the solution for “**A cylindrical copper cable 1.90km long is connected across a 220.0V -potential difference. What should be its…**“. We hope that you find a good answer and gain the knowledge about this topic of **science**.