A.) Draw the vector C⃗ =A⃗ +2B⃗ . B.)Draw the vector C⃗ =1.5A⃗ −3B⃗ . C.)Draw…
The following solution is suggested to handle the subject “A.) Draw the vector C⃗ =A⃗ +2B⃗ . B.)Draw the vector C⃗ =1.5A⃗ −3B⃗ . C.)Draw…“. Let’s keep an eye on the content below!
Question “A.) Draw the vector C⃗ =A⃗ +2B⃗ . B.)Draw the vector C⃗ =1.5A⃗ −3B⃗ . C.)Draw…”
A.) Draw the vector C⃗ =A⃗ +2B⃗ .
B.)Draw the vector C⃗ =1.5A⃗ −3B⃗
.
C.)Draw the vector C⃗ =0.5A⃗ +2B⃗
.
Answer
These concepts are used to draw vectors: vectors and the diagram.
To determine the relative magnitudes and order of the vectors in a combination, first use the concept vectors. Then, draw the vectors using the concept vector diagrams.
Vector is a physical quantity that has both magnitude and direction.
Vector addition is the operation of adding two or more vectors.
Vector diagrams are diagrams that show the relative magnitude and direction of a vector quantity using a vector arrow.
(A)
-Draw-the-vector-C⃗-=A⃗-+2B⃗-.-B.)Draw-the-vector-C⃗-=1.5A⃗-−3B⃗-.-C.)Draw.png?x-oss-process=image/resize,w_560/format,webp)
was created by
-Draw-the-vector-C⃗-=A⃗-+2B⃗-.-B.)Draw-the-vector-C⃗-=1.5A⃗-−3B⃗-.-C.)Draw.png?x-oss-process=image/resize,w_560/format,webp)
-Draw-the-vector-C⃗-=A⃗-+2B⃗-.-B.)Draw-the-vector-C⃗-=1.5A⃗-−3B⃗-.-C.)Draw.png?x-oss-process=image/resize,w_560/format,webp)
represents the unit vector in the x_ direction.
-Draw-the-vector-C⃗-=A⃗-+2B⃗-.-B.)Draw-the-vector-C⃗-=1.5A⃗-−3B⃗-.-C.)Draw.png?x-oss-process=image/resize,w_560/format,webp)
was created by
-Draw-the-vector-C⃗-=A⃗-+2B⃗-.-B.)Draw-the-vector-C⃗-=1.5A⃗-−3B⃗-.-C.)Draw.png?x-oss-process=image/resize,w_560/format,webp)
The vector HTMLmedia_tag_5$ combines vectors HTMLmedia_tag_0$ with vector
-Draw-the-vector-C⃗-=A⃗-+2B⃗-.-B.)Draw-the-vector-C⃗-=1.5A⃗-−3B⃗-.-C.)Draw.png?x-oss-process=image/resize,w_560/format,webp)
. It is provided by
-Draw-the-vector-C⃗-=A⃗-+2B⃗-.-B.)Draw-the-vector-C⃗-=1.5A⃗-−3B⃗-.-C.)Draw.png?x-oss-process=image/resize,w_560/format,webp)
In the above equation, substitute
-Draw-the-vector-C⃗-=A⃗-+2B⃗-.-B.)Draw-the-vector-C⃗-=1.5A⃗-−3B⃗-.-C.)Draw.png?x-oss-process=image/resize,w_560/format,webp)
in place of and HTMLmedia_tag_11$ in order to make the
-Draw-the-vector-C⃗-=A⃗-+2B⃗-.-B.)Draw-the-vector-C⃗-=1.5A⃗-−3B⃗-.-C.)Draw.png?x-oss-process=image/resize,w_560/format,webp)
as follows:
-Draw-the-vector-C⃗-=A⃗-+2B⃗-.-B.)Draw-the-vector-C⃗-=1.5A⃗-−3B⃗-.-C.)Draw.png?x-oss-process=image/resize,w_560/format,webp)
The vector diagram for the vectors is shown in the following figure.
-Draw-the-vector-C⃗-=A⃗-+2B⃗-.-B.)Draw-the-vector-C⃗-=1.5A⃗-−3B⃗-.-C.)Draw.png?x-oss-process=image/resize,w_560/format,webp)
-Draw-the-vector-C⃗-=A⃗-+2B⃗-.-B.)Draw-the-vector-C⃗-=1.5A⃗-−3B⃗-.-C.)Draw.png?x-oss-process=image/resize,w_560/format,webp)
has a magnitude of 4, and is directed along a positive _x_ axis. Vector
-Draw-the-vector-C⃗-=A⃗-+2B⃗-.-B.)Draw-the-vector-C⃗-=1.5A⃗-−3B⃗-.-C.)Draw.png?x-oss-process=image/resize,w_560/format,webp)
has a magnitude of 1, and is directed along a negative _x_- axis.
(B)
-Draw-the-vector-C⃗-=A⃗-+2B⃗-.-B.)Draw-the-vector-C⃗-=1.5A⃗-−3B⃗-.-C.)Draw.png?x-oss-process=image/resize,w_560/format,webp)
was created by
-Draw-the-vector-C⃗-=A⃗-+2B⃗-.-B.)Draw-the-vector-C⃗-=1.5A⃗-−3B⃗-.-C.)Draw.png?x-oss-process=image/resize,w_560/format,webp)
-Draw-the-vector-C⃗-=A⃗-+2B⃗-.-B.)Draw-the-vector-C⃗-=1.5A⃗-−3B⃗-.-C.)Draw.png?x-oss-process=image/resize,w_560/format,webp)
represents the unit vector in x direction, and #media_tag_20$ represents the unit vector in direction y direction.
-Draw-the-vector-C⃗-=A⃗-+2B⃗-.-B.)Draw-the-vector-C⃗-=1.5A⃗-−3B⃗-.-C.)Draw.png?x-oss-process=image/resize,w_560/format,webp)
was created by
-Draw-the-vector-C⃗-=A⃗-+2B⃗-.-B.)Draw-the-vector-C⃗-=1.5A⃗-−3B⃗-.-C.)Draw.png?x-oss-process=image/resize,w_560/format,webp)
-Draw-the-vector-C⃗-=A⃗-+2B⃗-.-B.)Draw-the-vector-C⃗-=1.5A⃗-−3B⃗-.-C.)Draw.png?x-oss-process=image/resize,w_560/format,webp)
combines vectors HTMLmedia_tag_24$ with vector
-Draw-the-vector-C⃗-=A⃗-+2B⃗-.-B.)Draw-the-vector-C⃗-=1.5A⃗-−3B⃗-.-C.)Draw.png?x-oss-process=image/resize,w_560/format,webp)
. It is provided by
-Draw-the-vector-C⃗-=A⃗-+2B⃗-.-B.)Draw-the-vector-C⃗-=1.5A⃗-−3B⃗-.-C.)Draw.png?x-oss-process=image/resize,w_560/format,webp)
In the above equation, substitute
-Draw-the-vector-C⃗-=A⃗-+2B⃗-.-B.)Draw-the-vector-C⃗-=1.5A⃗-−3B⃗-.-C.)Draw.png?x-oss-process=image/resize,w_560/format,webp)
and HTMLmedia_tag_29$ to get #media_tag_30$
-Draw-the-vector-C⃗-=A⃗-+2B⃗-.-B.)Draw-the-vector-C⃗-=1.5A⃗-−3B⃗-.-C.)Draw.png?x-oss-process=image/resize,w_560/format,webp)
(C)
-Draw-the-vector-C⃗-=A⃗-+2B⃗-.-B.)Draw-the-vector-C⃗-=1.5A⃗-−3B⃗-.-C.)Draw.png?x-oss-process=image/resize,w_560/format,webp)
was created by
-Draw-the-vector-C⃗-=A⃗-+2B⃗-.-B.)Draw-the-vector-C⃗-=1.5A⃗-−3B⃗-.-C.)Draw.png?x-oss-process=image/resize,w_560/format,webp)
-Draw-the-vector-C⃗-=A⃗-+2B⃗-.-B.)Draw-the-vector-C⃗-=1.5A⃗-−3B⃗-.-C.)Draw.png?x-oss-process=image/resize,w_560/format,webp)
represents the unit vector in x direction, and
-Draw-the-vector-C⃗-=A⃗-+2B⃗-.-B.)Draw-the-vector-C⃗-=1.5A⃗-−3B⃗-.-C.)Draw.png?x-oss-process=image/resize,w_560/format,webp)
represents the unit vector in direction y direction.
-Draw-the-vector-C⃗-=A⃗-+2B⃗-.-B.)Draw-the-vector-C⃗-=1.5A⃗-−3B⃗-.-C.)Draw.png?x-oss-process=image/resize,w_560/format,webp)
was created by
-Draw-the-vector-C⃗-=A⃗-+2B⃗-.-B.)Draw-the-vector-C⃗-=1.5A⃗-−3B⃗-.-C.)Draw.png?x-oss-process=image/resize,w_560/format,webp)
-Draw-the-vector-C⃗-=A⃗-+2B⃗-.-B.)Draw-the-vector-C⃗-=1.5A⃗-−3B⃗-.-C.)Draw.png?x-oss-process=image/resize,w_560/format,webp)
combines vectors HTMLmedia_tag_39$ with vector
-Draw-the-vector-C⃗-=A⃗-+2B⃗-.-B.)Draw-the-vector-C⃗-=1.5A⃗-−3B⃗-.-C.)Draw.png?x-oss-process=image/resize,w_560/format,webp)
. It is provided by
-Draw-the-vector-C⃗-=A⃗-+2B⃗-.-B.)Draw-the-vector-C⃗-=1.5A⃗-−3B⃗-.-C.)Draw.png?x-oss-process=image/resize,w_560/format,webp)
In the above equation, substitute
-Draw-the-vector-C⃗-=A⃗-+2B⃗-.-B.)Draw-the-vector-C⃗-=1.5A⃗-−3B⃗-.-C.)Draw.png?x-oss-process=image/resize,w_560/format,webp)
-Draw-the-vector-C⃗-=A⃗-+2B⃗-.-B.)Draw-the-vector-C⃗-=1.5A⃗-−3B⃗-.-C.)Draw.png?x-oss-process=image/resize,w_560/format,webp)
-Draw-the-vector-C⃗-=A⃗-+2B⃗-.-B.)Draw-the-vector-C⃗-=1.5A⃗-−3B⃗-.-C.)Draw.png?x-oss-process=image/resize,w_560/format,webp)
for #media_tag_45$
-Draw-the-vector-C⃗-=A⃗-+2B⃗-.-B.)Draw-the-vector-C⃗-=1.5A⃗-−3B⃗-.-C.)Draw.png?x-oss-process=image/resize,w_560/format,webp)
Part A – Ans
-Draw-the-vector-C⃗-=A⃗-+2B⃗-.-B.)Draw-the-vector-C⃗-=1.5A⃗-−3B⃗-.-C.)Draw.png?x-oss-process=image/resize,w_560/format,webp)
Part B
-Draw-the-vector-C⃗-=A⃗-+2B⃗-.-B.)Draw-the-vector-C⃗-=1.5A⃗-−3B⃗-.-C.)Draw.png?x-oss-process=image/resize,w_560/format,webp)
Part C
-Draw-the-vector-C⃗-=A⃗-+2B⃗-.-B.)Draw-the-vector-C⃗-=1.5A⃗-−3B⃗-.-C.)Draw.png?x-oss-process=image/resize,w_560/format,webp)
Conclusion
Above is the solution for “A.) Draw the vector C⃗ =A⃗ +2B⃗ . B.)Draw the vector C⃗ =1.5A⃗ −3B⃗ . C.)Draw…“. We hope that you find a good answer and gain the knowledge about this topic of science.