A light ray travels inside a block of sodium fluoride that has index of refraction n…
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Question “A light ray travels inside a block of sodium fluoride that has index of refraction n…”
A light ray travels inside a block of sodium fluoride that has
index of refraction n = 1.33 .The ray strikes the vertical
wall at the critical angle, totally reflects, and then emerges into
the air above the block. What is the angle ?2 at which the
ray emerges?
Answer
Snell’s law, which uses the variables angle of incidence (or refraction) to solve the problem, is used to solve it.
First, use Snell’s law to express the relationship using the variables index of reflection of first medium, index de refraction second medium, angle d’incidence and refraction. Next, reorganize the expression to calculate critical angle. Next, use Snell’s law to express the relationship in terms of angle and incidence. To calculate the angle of the emerging ray, you can modify the expression by substituting the angle of incidence values.
The refractive index calculated using Snell’s law.
The critical angle is the angle of reflection, which is the refractive indices of the first medium and the refractive indices of the second.
The refractive index calculated using Snell’s law.
Substitute
for
and
to
.
The refractive index is the expression.
Modify the expression according to
Substitute
to
,
to
, and
to
Ans:
is the angle of emerging Ray.
Conclusion
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