**A light ray travels inside a block of sodium fluoride that has index of refraction n…**

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## Question “A light ray travels inside a block of sodium fluoride that has index of refraction n…”

A light ray travels inside a block of sodium fluoride that has

index of refraction *n* = 1.33 .The ray strikes the vertical

wall at the critical angle, totally reflects, and then emerges into

the air above the block. What is the angle *?*2 at which the

ray emerges?

## Answer

Snell’s law, which uses the variables angle of incidence (or refraction) to solve the problem, is used to solve it.

First, use Snell’s law to express the relationship using the variables index of reflection of first medium, index de refraction second medium, angle d’incidence and refraction. Next, reorganize the expression to calculate critical angle. Next, use Snell’s law to express the relationship in terms of angle and incidence. To calculate the angle of the emerging ray, you can modify the expression by substituting the angle of incidence values.

The refractive index calculated using Snell’s law.

The critical angle is the angle of reflection, which is the refractive indices of the first medium and the refractive indices of the second.

The refractive index calculated using Snell’s law.

Substitute

for

and

to

.

The refractive index is the expression.

Modify the expression according to

** **

Substitute

to

,

to

, and

to

Ans:

is the angle of emerging Ray.

## Conclusion

Above is the solution for “**A light ray travels inside a block of sodium fluoride that has index of refraction n…**“. We hope that you find a good answer and gain the knowledge about this topic of **science**.