**An ice skater has a moment of inertia of 5.0 kg-m^2 when her arms are outstretched….**

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## Question “An ice skater has a moment of inertia of 5.0 kg-m^2 when her arms are outstretched….”

An ice skater has a moment of inertia of 5.0 kg-m^{2} when her arms are outstretched. At this time she is spinning at 3.0 revolutions per second (rps). If she pulls in her arms and decreases her moment of inertia to 2.0 kg-m^{2}, how fast will she be spinning?

A) 7.5 rps

B) 8.4 rps

C) 2.0 rps

D) 10 rps

E) 3.3 rps

## Answer

Conservation of angular momentum

Because there is no external torque acting

I_{1}w_{1} = I_{2}w_{2}

5.0*3 = 2.0 w_{2}

w _{2} = 7.5% rps

## Conclusion

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