**An ultracentrifuge accelerates from rest to 100,000 rpm in 2.00 min. (a) What is its angular…**

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## Question “An ultracentrifuge accelerates from rest to 100,000 rpm in 2.00 min. (a) What is its angular…”

An ultracentrifuge accelerates from rest to 100,000 rpm in 2.00 min. (a) What is its angular acceleration in rad/s2, rad/s2 (b) What is the tangential acceleration (in m/s2) of a point 9.00 cm from the axis of rotation? m/s2 (c) What is the radial acceleration in m/s2 and multiples of g of this point at full rpm? a in m/s m/s2 a as a multiple of g 9

## Answer

The Ultracentrifuge can accelerate from 100,000 to sest apon in just 2 minutes. first we will convert rpm into rad’s. 100 000 (270). : 10472 Radls’ 60. Angular acceleration can be given by, x=lf 174.5 10472 rad’s 2 6os/52 (6) Tangential acceleration at a Point 9cm from the sotation.axls. 174.5 (94162) = 15.70m/s2 at =xra pourquoi (e) Radial acceleration is calculated by the formula, Q= (10472) 2 (0.09 = 9.8x10m/s2 In terms get well be 6, 9.8x106m/s2 1410g 9.8x10m/s2 100g

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