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Arrange the species O2+, O2, O2-, O2^(2-) in order of increasing O-O bond length? Thanks!

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Question “Arrange the species O2+, O2, O2-, O2^(2-) in order of increasing O-O bond length? Thanks!”

Arrange the species O2+, O2, O2-, O2^(2-) in order of increasing
O-O bond length?

Thanks!

Answer

Concepts and Reason

These types of problems can be solved using the molecular orbital theory. Molecular orbital theory states that two atomic orbitals combine to form two or more molecular orbitals.

Calculate the valance electrons for all species. Next, write down the molecular electronic configuration for each species. Finally, calculate the bond order.

Fundamentals


Bond Order:

The number of chemical bonds that exist between two atoms is called bond order.

Use the following formula to determine the bond order for any molecule.

Bond order - Bonding e- Antibonding e 2

……(1)


Bond length

The bond length is the distance between two atoms that form a covalent bond.

The relationship between the bond order and bond length is:


1 Bond order oc Bond length


According to the above relationship, the shorter the bond order is, the longer the bond length. Conversely, the lower the bond order the longer the bond length.

Below is the electronic configuration for O 2 +.


(ols)2 (o*1s)2 (o2s)? (*2s) (02p,)2 (T2p,(n2p,) (n*2p.)(t2p,)


In equation (1), substitute the electrons’ values in antibonding orbitals for those in bonding orbitals.

Now,


Bond order Bonding e- Antibonding e 2


=

10-5 2

=

2.5

The electronic configuration for O 2 – can be found here:


|G1s)2 (G*1s) (G2s)2 (o*2s)? (o2p,)2 (n2p.(72p,) (n*2p,°(n*2p,)


In equation (1), substitute the electrons’ values in antibonding orbitals for those in bonding orbitals.

Now,

Bond order =

bonding e- antibonding e 2

=

10-7 2

=

1.5

Below is the electronic configuration for

O2

.


|G1s)? (G*1s) (G2s) (o*2s) (02p,)2 (n2p,)(72p,)* (x*2p,°(x*2p,)


Now,

Bond order =

bonding e- antibonding e 2

=

10-6 2

= 2

The electronic configuration for O 2 2- are:


|G1s)2 (G*1s) (G2s)2 (o*2s)? (02p,)2 (T2p.j(72p,) (n*2p,°(n*2p,)


Now,

Bond order =

bonding e- antibonding e 2

=

10-8 2

=

The species’ bond order is:



Species Bond order O2t 2.5 Ог 1.5 O2 2 O22- 1



Below is an illustration of the increasing order O-O bond length


O;<o2<02<0


Ans:


Below is A graph showing the increasing O-O bond length.


O;<o2<02<0


Conclusion

Above is the solution for “Arrange the species O2+, O2, O2-, O2^(2-) in order of increasing O-O bond length? Thanks!“. We hope that you find a good answer and gain the knowledge about this topic of science.


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