Balancing Oxidation–Reduction Reactions (Section)Complete and balance the following equations, and identify the oxidizing and reducing agents:(a)…

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Question “Balancing Oxidation–Reduction Reactions (Section)Complete and balance the following equations, and identify the oxidizing and reducing agents:(a)…”

Balancing Oxidation–Reduction Reactions (Section)

Complete and balance the following equations, and identify the oxidizing and reducing agents:

(a) Cr2O72-(aq) + I–(aq)→Cr3+(aq) + IO3–(aq) (acidic solution)

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(b) MnO4–(aq) + CH3OH(aq) →Mn2+(aq) +HCO2H(aq) (acidic solution)

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(c) I2(s) + OCl–(aq)→IO3–(aq) + Cl–(aq) (acidic solution)

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(d) As2O3(s) + NO3–(aq)→H3AsO4(aq) + N2O3(aq) (acidic solution)

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(e) MnO4–(aq) + Br–(aq)→MnO2(s) + BrO3–(aq) (basic solution)

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(f) Pb(OH)42-(aq) + ClO–(aq)→PbO2(s) + Cl–(aq) (basic solution)

Answer

(a)

Two halves cell reactions

To equalize the number of oatoms, add

To equalize the H-atoms, add

To offset the charge

Overall equation: –

Add the equation above

(b)

Two halves cell reactions

To equalize the O-atoms, add

To equalize the H-atom number, add

To offset the charge:

Multiplied equation (1) multiplied by 4 and (2) multiplied by 5

Add both to get the overall equation

Change in the oxidation state

can oxidize, but it is also reduced so

can be used as a reducing agent.

(c)

Two halves cell reactions

To equalize the O-atom number by adding

To equalize the H-atoms, add

To offset the charge

Multiplied equation (2) multiplied by 5

Add both equations to get the overall reaction

The oxidation state of I or C1 is changed.

can be oxidized, so it’s a reducer and is an oxidizing agent.

(d)

Two halves cell reactions

To equalize the O-atom number, add

To equalize the H-atom number, add

To offset the charge:

Add the two reactions to get an overall reaction

Change in the oxidation state

.

can be oxidized, so it’s a reducer and an oxidizing agent.

(e)

Two halves cell reactions

To equalize the O-atoms, add

To equalize the H-atoms, add

To offset the charge:

Multiplied equation

and added to both

The reaction

Overall reaction:

Change in the oxidation state

.

is reduced, thus it’s an oxidizing agent and is a reducing agent.

(f)

Two halves cell reactions

To equalize the O-atom number, add

To balance the number of H-atom by adding

-:

To offset the charge:

Add the equations as follows:

To neutralize ion we added HTMLMediaTag98 on both sides-

How to determine the state of oxidation change

can be oxidized, so it’s a reducer and an oxidizing agent.

Conclusion

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