Based on the bond angles in CH4, NH3, and H2O. rank the magnitude of these repulsions….
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Question “Based on the bond angles in CH4, NH3, and H2O. rank the magnitude of these repulsions….”
Answer
This question is based upon the magnitude of repulsion among the bond pairs and the lone pairs in the given molecules.
All molecules given exhibit the same degree of hybridization. However, not all compounds with the same hybridization must have identical bond angles. The repulsions between bond pairs and single pairs determine the bond angles.
Hybridization refers to the mixing of atomic orbitals with similar energy to create hybrid orbitals having lower energy than their former.
VSEPR theory can be used to determine hybridization of the central element of any compound.
The number of electron pairs is the sum of all bond pairs and lone pair in a compound. The VSEPR theory states that the number of electron pairs determines the degree of hybridization.
There are three types of repulsions that can occur in a molecule depending on how many bond pairs or lone pairs are present. These are:
* Bond pair – Bond couple: This occurs between two bonds.
* Bond pair – Lone couple: This occurs between a lone and bond.
* Lone couple – It is between two lone couples.
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hybridized using VSEPR theory. Their expected geometry should have a tetrahedral with bond angles of
.
The observed bond angles and the shapes of these bonds are:
molecules, there will be no bond pair -bond pairing repulsion.
will have two forces that are repulsive: bond pair-bond couple and lone bond pair.
will have three repulsions: bond pair-bond pair, bond couple-lone-pair, bond pair-lone-pair, and bond pair-lone-pair. This is due to the presence two lone pairs.
Ans:
This is the order of magnitude of repulsion, from strongest to most weakest: