Consider the following reaction: CO2(g)+CCl4(g)⇌2COCl2(g) Calculate ΔG for this reaction at25 ∘C under these conditio…
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Question “Consider the following reaction: CO2(g)+CCl4(g)⇌2COCl2(g) Calculate ΔG for this reaction at25 ∘C under these conditio…”
Consider the following reaction:
CO2(g)+CCl4(g)⇌2COCl2(g)
Calculate ΔG for this reaction at25 ∘C under these
conditions:
PCO2=0.100atm
PCCl4=0.160atm
PCOCl2=0.760atm
ΔG∘f for CO2(g) is −394.4kJ/mol, ΔG∘f for CCl4(g) is
−62.3kJ/mol, and ΔG∘f for COCl2(g) is −204.9kJ/mol.
Express the energy change in kilojoules per mole to one
decimal place.
Answer
CO2(g) + CCl4(g) = 2COCl2(g)
That is what we know.
DG Rxn = DGH 0 Rxn + T lnQ
These dGf’s CO2(g)= -394.4 KJ/mol
CCl4 (g)= -62.3 kJ/mol
COCl2 (g)= -204.9 kJ/mol
If your text has a different dGf, you’ll need to do these calculations again
We first locate the standard dG reaction
Go = [products-reactants]
Go = [ 2 (-204.9 kJ/mol)] – [(-394.4 kJ/mol) + (- 62.3 kJ/mol)]
Go = – 409.8 kJ/mol – (-456.7 kJ/mol)
Go = – 409.8 kJ/mol + 456.7 kJ/mol
Go = + 46.9 kJ/mol
We now use
Grxn =
G0rxn + RT lnQ
G = + 46.9 kJ/mol + (0.008314 kJ/mol K) (298 K) ln ( [COCl2]2 / [CO2] [CCl4] )
G = + 46.9 kJ/mol + (0.008314 kJ/mol K) (298 K) ln ( [0.760]2 / [0.100] [0.160] )
G = + 46.9 kJ/mol + (0.008314 kJ/mol K) (298 K) ln ( 36.10)
G = + 46.9 kJ/mol + (2.4776 kJ/mol) (3.586)
G = + 46.9 kJ/mol + 8.88 kJ/mol
G = 55.78 kJ/mol
G = 55.8 kJ/mol
Conclusion
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