Construct a simulated 1H NMR spectrum, including proton integrations, for CH3CHCl2. Drag the appropriate splitting patterns…
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Question “Construct a simulated 1H NMR spectrum, including proton integrations, for CH3CHCl2. Drag the appropriate splitting patterns…”
Construct a simulated 1H NMR spectrum, including proton
integrations, for CH3CHCl2. Drag the appropriate splitting patterns
to the approximate chemical shift positions; place the integration
values in the small bins above the associated chemical shift.
Splitting patterns and integrations may be used more than once, or
not at all, as needed. Likewise, some bins might remain blank. Note
that peak heights are arbitrary and do not indicate proton
integrations.
Answer
1H NMR Spectroscopy:
* Nuclear magnetic resonance is a widely-used technique in analytical chemistry. It can be used to determine the purity and structure of samples.
* The spectroscopy detects when the frequency at which the nuclei (samples) of an atom resonates with the frequency associated with the rotating magnetic field.
* Spectroscopy is used to determine the types of hydrogen atoms present in a molecule (chemically non-equivalent hydrogen Atoms).
1HNMR Spin-Spin Coupling Designs:
Number of hydrogen atoms that are chemically non-equivalent to each other n | Number of peaks | Splitting Name | Ratio of peak heights |
0 | 1 | Singlet | |
1 | 2 | Doublet | |
2 | 3 | Triplet | |
3 | 4 | Quartet |
This is used to determine if the product obtained matches the product expected in a reaction mix.
The given organic compound is 1,1 -dichloroethane. Below is the structure of this compound.
This structure contains two non-equivalent protons.
The number of hydrogen atoms adjacent to methyl proton is 1. This proton will have a doublet (around 1ppm) in the 1H NMR spectrum.
For a chlorine-substituted proton
, the number of adjacent hydrogen atoms is 3. This proton will therefore show a quartet (around 5.5%) in the 1H NMR spectrum.
The 1H NMR spectrum of the compound is therefore shown below.
Ans:
Below is the 1H NMR spectrum of the compound.
Conclusion
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