Determine the molar solubility of AgBr in a solution containing 0.150 M NaBr. Ksp (AgBr) = 7.7 × 10-13.

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Question “Determine the molar solubility of AgBr in a solution containing 0.150 M NaBr. Ksp (AgBr) = 7.7 × 10-13.”

Answer

Solubility product

The solubility product is basically the equilibrium between solids, and their respective ions in the solution. The solubility product is the amount of chemical compound that can be dissociated in water.

Exemple:

Below is the dissociation reaction for ionic solid

.

Below is the expression that corresponds to the solubility products.

The following is the balanced chemical equation for dissociation reaction of

:

Below is the expression that corresponds to the solubility products.

…… (1)

As shown below, the molar solubility

has been calculated.

Consider the

as the molar solubility for the compound.

Substitute

for the concentration of bromide and

for the

from

.

Ans:

has a molar solubility value of

.

Conclusion

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