Draw the alkene formed when 1-heptyne is treated with one equivalent of HBr.
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Question “Draw the alkene formed when 1-heptyne is treated with one equivalent of HBr.”
Draw the alkene formed when 1-heptyne is treated with one equivalent of HBr.
Answer
Alkyne and hydrogen halide are combined to make an alkenyl-halide product. This reaction is a continuation of Markovnikov’s addition pathway.
Markovnikov’s addition: Markovnikov’s addition of hydrogen to alkyne creates the most stable alkene.
Markovnikov’s rule states that hydrogen halide with a negatively charged addendum is linked to carbon atoms.
Below is an illustration of the alkyne structure.
reaction to the Hept-1-yne shown below.
In this addition reaction, nucleophile is
(bromide ion).
Below is a nucleophilic attack against the intermediate
The general reaction is as follows.
Ans:
Below is A picture of the alkene produced during the addition reaction.
Conclusion
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