Draw the Lewis structure for SeS3 and answer the following questions. How many valence electrons are…
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Question “Draw the Lewis structure for SeS3 and answer the following questions. How many valence electrons are…”
questions.
How many valence electrons are present in this compound?
How many bonding electrons are present in this compound?
How many lone pair (non-bonding) electrons are present in this
compound?
Answer
The Lewis structure provides a detailed explanation of the connectivity of the atoms within the molecule, and also shows the lone pair electrons of the atoms in that molecule.
Valence electrons are electrons that reside in the outermost shells of atoms and can participate in bonding.
Octet rule. According to the octet law, an atom will be stable if it contains eight electrons within its outermost shell (valence shell). To satisfy the octet rules, most of the atoms will accept or donate electrons to their outermost orbitals.
These are the steps required to draw a Lewis structure:
Step 1: Determine the number of valence elements.
Step 2: Determine the number of electrons required to complete the atom’s octet.
Step 3: Find the number of bonds within the molecule.
Step 4: Select a central atom.
Step 5: Draw a skeletal framework.
Step 6: Add electrons to the atoms.
Example for Lewis structure

Water molecules contain one oxygen atom, and two hydrogen atoms. The valance electron for an oxygen atom is 6, and the hydrogen atom is 1.
Therefore, in total, there are

electrons. This molecule contains oxygen that is bonded to 2 hydrogen atoms. For 2 bonds, 4 electrons are required. The remaining 4 electrons, which form the bonds, are non-bonded electrons. These electrons are called lone pairs electrons.

.

Lewis structure is as follows:


.
The number of valence elements in sulfur is
The number of valence elements in selenium has been determined to be

Find the bonding electrons using the Lewis structure of

.



total number of bonding electrons.
You can find the lone pair of electrons by using the Lewis structure of

.



is the total number of non-bonding lone pairs.
Ans:


.

is the number of non-bonding lone pairs in this compound.
Conclusion
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