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Draw the Lewis structures of C2H6, C2H4, and C2H2. Draw the molecules by placing atoms on…

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Question “Draw the Lewis structures of C2H6, C2H4, and C2H2. Draw the molecules by placing atoms on…”

Draw the Lewis structures of C2H6, C2H4, and C2H2.
Draw the molecules by placing atoms on the grid and connecting them
with bonds. Include all hydrogen atoms.

Answer

Concepts and Reason

This question can be solved by calculating the Lewis structures and structural formulas for the molecules. You can calculate the number of valence electrons that surround the atoms of the given molecules to create the Lewis structure. The structure of the molecules is represented by the formula that shows the bonds between the atoms.

Fundamentals

Lewis structure: The molecular chemical behavior can be understood through its structure. This includes the distribution of electrons around each atom as well as type of bonding (single or double, triple). The electron distribution around the atoms of a molecule is called the Lewis structure. This structure is also known by the electron dot structure, which has the following features.

1) These structures only take into consideration valence electrons.

2) These clearly demonstrate bonding and nonbonding electrons.

3) All atoms must follow the duet and octet rules.

Octet rule This states that the atoms of main-group elements in a molecule form bonds in such a manner that it has eight electrons within its valence shell.

Structural Formula: This is the structure of a molecule that contains all the bonds created by placing the atoms within the framework. It provides information about the arrangement and composition of the atoms within the molecule.

The formula for the molecule $math_tag_0 is given

4.

1.

The total number of valences electrons in a given molecule can thus be calculated as follows:

\begin{array}{c}\\{\rm{2(C) + 6(H) = 2(4) + 6(1)}}\\\\{\rm{ = 8 + 6}}\\\\{\rm{ = 14 valence electrons}}\\\end{array}

These 14 electrons must be placed in the Lewis structure.

Only one bond can be formed by hydrogen and four can be formed by carbon.

Draw the Lewis structure of individual atoms C or H.



Two electrons can form a single covalent bond (single bonds) between two atoms. The octet rule should be followed by the C-atom of the molecule.

The Lewis structure of {{\rm{C}}_{\rm{2}}}{{\rm{H}}_{\rm{6}}} is a result.


Η Η Η:C:C: Η Η Η


The formula for the molecule $math_tag_3 is given

The number of valence elements in a carbon atom is 4.

The hydrogen atom has 1.

The total number of valences electrons in a given molecule can thus be calculated as follows:

\begin{array}{c}\\{\rm{2(C) + 4(H) = 2(4) + 4(1)}}\\\\{\rm{ = 8 + 4}}\\\\{\rm{ = 12 valence electrons}}\\\end{array}

These 12 electrons must be placed in the Lewis structure.

Only one bond can be formed by hydrogen and four can be formed by carbon.

Draw the Lewis structure of individual atoms C or H.



Two electrons can form a single covalent bond (single bonds), while four electrons may form a double bond between atoms. The octet rule should be followed by the C-atom of the molecule.

The Lewis structure of {{\rm{C}}_{\rm{2}}}{{\rm{H}}_{\rm{4}}} is a result.



$math_tag_6 is the formula for the molecule.

The number of valence elements in a carbon atom is 4.

The hydrogen atom has 1.

The total number of valences electrons in a given molecule can thus be calculated as follows:

\begin{array}{c}\\{\rm{2(C) + 2(H) = 2(4) + 2(1)}}\\\\{\rm{ = 8 + 2}}\\\\{\rm{ = 10 valence electrons}}\\\end{array}

These 10 electrons must be placed in the Lewis structure.

Only one bond can be formed by hydrogen and four can be formed by carbon.

You can write the Lewis structure for individual atoms C or Hs as follows:



Two electrons can form a single covalent bond (single bonds), while six electrons may form a triple bond between atoms. This molecule’s C-atom should be following the octet rules.

The Lewis structure of {{\rm{C}}_{\rm{2}}}{{\rm{H}}_2} is a result.


H:C:::C:H


The Lewis structure for $math_tag_0


Η Η Η:: : Η Η Η


The Lewis structure above shows that a pair electrons can form a single bond.

This means that a single bond exists between two C-atoms, and each carbon atom has three single bonds containing three hydrogen atoms.

The structural formula for {{\rm{C}}_{\rm{2}}}{{\rm{H}}_{\rm{6}}} is therefore applicable.


Η Η H—C—C—H Η Η


The Lewis structure for {{\rm{C}}_{\rm{2}}}{{\rm{H}}_{\rm{4}}}


H.C::C H


The Lewis structure above shows that a single bond is formed by a pair electrons.

This means that a double bond exists between two C-atoms, and each carbon atom has 2 single bonds with 2 hydrogen atoms.

The structural formula for {{\rm{C}}_{\rm{2}}}{{\rm{H}}_{\rm{4}}} is therefore applicable.


H


The Lewis structure for $math_tag_13


H:C:::C:H


The Lewis structure above shows that a pair electrons can form a single bond.

A triple bond exists between two C-atoms, and each carbon atom is bound with one hydrogen atom.

The structural formula for {{\rm{C}}_{\rm{2}}}{{\rm{H}}_{\rm{2}}} is therefore applicable.


H-C=C—H


Ans: Part 1.a

The Lewis structure for $math_tag_0


Η Η Η:C:C: Η Η Η


Part 1.b

The Lewis structure for {{\rm{C}}_{\rm{2}}}{{\rm{H}}_{\rm{4}}}



Part 1.c

The Lewis structure for $math_tag_6


H:C:::C:H


Part 2.a

The structural formula for $math_tag_0


Η Η H—C—C—H Η Η


Part 2.b

The structural formula for $math_tag_3


H


Part 2.c

The structural formula for $math_tag_13


H-C=C—H


Conclusion

Above is the solution for “Draw the Lewis structures of C2H6, C2H4, and C2H2. Draw the molecules by placing atoms on…“. We hope that you find a good answer and gain the knowledge about this topic of science.


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