Draw the products of the given reaction. Include all appropriate hydrogen atoms and charges. Draw products….
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Question “Draw the products of the given reaction. Include all appropriate hydrogen atoms and charges. Draw products….”
Draw the products of the given reaction. Include all appropriate hydrogen atoms and charges. Draw products. Select Draw Rings More Erase H2C NH2 CH-CH2 + H H3C 1e13 @lale
Complete the reaction. Add hydrogen atoms and charges to the appropriate atoms. Select Draw Rings More Erase ZICH NOC HCI CH3 -CH2-C-N-CH3 + H laoreet –!-:– heat
Answer
Answer 1
In our reaction Amine +H2O as. Me me dauna vita + Micco-wohy-ning Me H : Hao Water) Amine 8H single pair donate – These act as lewis bases due to the presence of one part on amines. Ot donaty lone electron pair. Yelectron donos) When there is hao. This is due to electronegativity difference of nitrogen 3.04 atom and oxygen 3-44. N- is the only papr that is available for donation. O-H bond $ 700 is possible to break (due electronegati vity Clifference ble and Hydrgan atom round). Tell Guculate “ht&csily bond weak. For donation Our At knockout and accepted by Due to the whole these upper points act as base-RNHO ta. base aud R-NH2 R + OH nan
WUUUUUUUUUUUUUUUUUUUUWWWWWWWWWWWWWWWWWWWW As amine au as base and to act as aud (donale Ht). Bronsted’s conjugate acid bode theory. Lauborylic ammium ion + amino + H20 Hydroegue au amides in the preunce of H+. AS Hao: A weak nucleophile (nucleust loving, having lone pour electrong), it is impossible for Hyo attack on Antide. 20 Anual R–C5NH2+/Ho: X This is because Hoo weak nucleophile. – ab (albon cense is weak electrofee) But in the presence and, mou electrophile center on cubon Atom i produced from protonation Paudic medium. This was because of coton auid C- R-C – NHg less electron potonation pootonation equiur’n tul charge shift on caebon atom R-G-NH2 on. Because Oxygen has two lone pairs Now an ostrong (electrophilll(eletront louring) center. ie accepts electrons easily. as. C (0) aeOH – Nng Trong As On donate R–C/- uhg7 6) Bora (P070) pair to pransfer its single Carbone on Pt. The charge – OH R-C- o t k DIH Acid
UUUUUWWWWWWWWWWWWWWWWWWWWW WW to Reaction path (6) and (0) – (6) + when two atoms like oxygen and Nitrogen present then 67 Swift to lower clectronegative otom. ie. O N ShiftHT (0 pz due the positive charge easily knocked down from the molecular. This is a breakge of bond facelitate according to rumoures of it from -OH puthis bond automatic break. NH3 – H – R- & + NH3 HT uvabency exceed than 4 Now your given ron. Reaction is go amide like do some react Qud, join yechd–gp–cony N– – heat 2: 2 Amide Shechy & N– CH3 OH OH H2C–CH -cd–ch Ht transfer — ias si.
Answer 2
Answer 3
Conclusion
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