Draw the structure of the product formed when 2-methylbutanal is treated with cold aqueous base. Draw…
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Question “Draw the structure of the product formed when 2-methylbutanal is treated with cold aqueous base. Draw…”
Draw the structure of the product formed when 2-methylbutanal is
treated with cold aqueous base.
Answer
* The condensation reaction is an important type of chemical reaction in organic synthesis.
* This reaction results in the formation of a double carbon-carbon bond. A type of condensation reaction called an aldol condensation reaction involves two aldehydes with a-hydrogen molecules that react to each other to create an aldol product.
* First, the aldol reaction is performed. This is where the enolate is formed. Then, it reacts with another aldehyde molecule.
* Dehydration of aldol product, forms ab-unsaturated carbonyl molecular (aldol). This is called an aldol condensation reaction.
* The base catalyzes the aldol reaction by deprotonating the acidic hydrogen of an a-carbon carbon atom to create the enolate.
* An enolate can be a good nucleophile or carbonyl {\rm{C}}
Two steps are required to create an aldol condensate. The first is an aldol react and the second is a dehydration elimination process. The base first removes the proton and forms a carbanion. Next, it attacks the carbonyl groups of other compounds to create an oxy anion. The compound is hydrolyzed to form an aldol. This is followed by dehydration which will produce an aldol product.
Mechanism:-
Ans:
Below is the structure of 2-methylbutsnal when it is mixed with cold aqueous bases.
Conclusion
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