**Find an equation of the line that satisfies the given conditions. Through (-1, -14); perpendicular to…**

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## Question “Find an equation of the line that satisfies the given conditions. Through (-1, -14); perpendicular to…”

Find an equation of the line that satisfies the given conditions. Through (-1, -14); perpendicular to the line passing through (2,-2) and (6,-4)

Find an equation of the line that satisfies the given conditions. Through (-9, 1); parallel to the line x = 7

Find an equation of the line that satisfies the given conditions. Through (1, 1); parallel to the line y = 9x – 7

Find an equation of the line that satisfies the given conditions. Through (9, -1); slope undefined

Find an equation of the line that satisfies the given conditions. x-intercept -4; y-intercept 2

## Answer

You can find the equation of (-1.14.4), and the line that passes perpendicularly to (12.2) 4. (6,4) The slope of the point the live (2.-2) in four passes (6-4). This is because the slope of the line their mm required is t through (2.-2) 4 slope multiplication to line (6-4). Therefore, it is equal to -mez Lx6 y = 2x + (n.4).

-14 = -14 – -21-1) + b – 2 + b b ba -14+9 = -12 Equation for the required line is Merc 2 Equation for the line that passes through I (9, 1) 4 parallel line x = 7 Answert x=r7 must be a vertical vertical line. Any line parallel to line x=7 must have the foomx “some constant” It is because the line passes through then the x that passes parallel = 9 is the I required through (-9.1) to x = 7.

(1,1) 3 The equation of a line passes through a parallel line y =9x – 7 Answer: – The slope of line 8x of line 9x is – 7. The slope of the requiredline is also 9. 9x + 1 It on, therefore, passes through (1,1)(x,y) es (1.1) answer: – Slope of line y 8x of line ya 9x – 7 i slope of the requiredline is also 9. The equation of the line that passes through (9-1) I and its slope undefined. Answer: Undefined slope means it is a vertically parallel line to the y-axis, pasting through all points on the plane with an coordinate x constant. The equation is in from x =c

The constant – coordinate is 19-1). Line is therefore the value that passes through the constant x = al. 4) Equation of line having the y intercept = 2tas. – The line passes of line have x intercept = 2 tas. – The x fy intercepts for line passes are &-4 and 2 through (-4.0) 4 (0.2) slope 8 – 0 0- (-u) 2 – of reg line – (-y exubx,y) + (-4.) + b) + -b. Rate

## Conclusion

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