Finding [OH-] which is 100 times greater than [H+]
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Question “Finding [OH-] which is 100 times greater than [H+]”
The problem is for part (c) below.Thank you.
Calculate [H+] for each of the following solutions,and indicate whether the solution is acidic, basic, orneutral.(a) [OH –] = 0.00041 M
M
(c) a solution in which [OH –] is 100 times greater than[H+]
Your answer differs from the correct answerby orders of magnitude. M
Answer
If pH is 1-6.9 then it is acidIf pH is 7.1 – 14 then it is Basea)pOH = -log[OH]=-log(0.00041)=3.38pH = 14-pOH= 14-3.38= 10.612So it is Baseb) pOH = -log(2.5*10
-9
)=8.602pH=14-pOH=14-8.602= 5.3 We know it is acidicc).
+
][OH
–
] =10
-14
Here [OH].
–
[H] is 100 times more effective than ]
+
]so 100[H
+
][H
+
] =10
-14
[H
+
] =10
-8
Concentration total of [H]
+
[H]
+
] =10
-7
+ 10
-8
= 10
-7
(1+0.1)=10
-7
(1.1)pH = -log[H
+
]=-log10
-7
It is acidic because it has 7-log (1.1)= 7-0.0413= 6.95
Conclusion
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