For the circuit shown in the figure, the switch S is initially open and the capacitor is…
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Question “For the circuit shown in the figure, the switch S is initially open and the capacitor is…”
For the circuit shown in the figure, the switch S is initially open and the capacitor is uncharged.
The switch is then closed at time t = 0. How many seconds after closing the switch will the
energy stored in the capacitor be equal to 50.2 mJ?
Answer
Concepts and Reason
This problem can be solved using the following concepts: maximum charge on a capacitor within an RC Circuit, charge as a function time in an RCC circuit, and energy inside a charged capacitor.
To find the energy stored within a capacitor, first use the relationship between charge and time as a function.
Next, calculate the relationship between voltage and capacitance to determine the maximum charge for a capacitor.
Finally, you can use charge as a function time in an RCC circuit to determine how long it takes for a capacitor to store
electricity.
Fundamentals
After the switch is closed the capacitor connects to the battery. The charge is then stored in the capacitor.
Charge as a function time is the expression
Here, time is
and resistance is
. Capacitance is
. Maximum charge on the capacitor:
. Charge as a function time is
.
The energy stored in the capacitor’s capacitor is described as
The maximum charge for a capacitor is
Here, the voltage value is
.
The energy stored in the capacitor’s capacitor is described as
electricity is over when the switch closes. It costs
.
Conclusion
Above is the solution for “For the circuit shown in the figure, the switch S is initially open and the capacitor is…“. We hope that you find a good answer and gain the knowledge about this topic of science.
