For the matrix A below, find a nonzero vector in Nul A and a nonzero vector…
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Question “For the matrix A below, find a nonzero vector in Nul A and a nonzero vector…”
For the matrix A below, find a nonzero vector in Nul A and a nonzero vector in Col A. 2 3 8-11 A=1-6-6-12 18 4 -3 -20 23
A matrix A and an echelon form of A are shown below. Find a basis for Col A and a basis for Nul A 1 2 02 A=177-21 351~1013-3 3 4 -6 12 3 3 -9 15
Answer
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{F(x) = e^x + 2x, 0 lessthanorequalto x lessthanorequalto 2 A = [2 -6 4 3 -6 -3 8 -12 -20 -11 823] similarto [1 0 0 2 1 0 0 3 0 2 -3 0] pivots element in column A F(x), = ex – 2x -6 -3 8-12 -20 -11 823] Similar to [10/0 2 10/0 3 10/0 3 10/0 3 10/0 3 10/0 3 10/0 3 1 0 3 1 0 1 0 3 1 0 1 0 1 0 1 0 1 0 1 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 3x_4 3x_4 3x_4 3x_4 3x_4 3x_2 3x_3 3x_2 3x_4 3x_4 3x_4 3x_2 3x_3 3 0 4 x_3 3 x_4 3 0 1 2x_4 3 x_2 2 x_3 3 0 1 2 x_2 2 0 1 3 x_2 3 x_4 3 x_3 1 0 1 3 0 1 3 x 0 1 3 0 1
Conclusion
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