**Four resistors are connected to a battery as shown in the figure. The current in the…**

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## Question “Four resistors are connected to a battery as shown in the figure. The current in the…”

## Answer

### Answer 1

### Answer 2

**SOLUTION :**

Equivalent of all resistors connected to the battery

= R1 + (1 / (1/(R2 + R3) + 1/R4)

= R + ( 1/(2R + 4R) + 1/(3R) )

= R + 1/( ( 1 + 2) / (6R))

= R + 1/(1/(2R))

= R + 2R

= 3R

So, current flow from the battery, I

= V / (3R) = 6.90 / (3R)

= 2.30/ R amps.

**Voltage , v1, across resistor R1 **

= I * R

= 2.30 / R * R

**= 2.30 volts .**

So, voltage across resistors (R2 + R3)

= 6.90 – 2.30 = 4.60 volts.

But, R2 + R3 = 2R + 4R = 6R

So, current through (R2 + R3)

= 4.60 / (6R)

= 0.7667 / R

**So, voltage v2 across R2 **

= 0.7667 / R * 2R

**= 1. 533 volts **

**So, voltage across R3 **

= 4.60 – 1.533

**= 3.067 volts (ANSWER).**

**Voltage across R4 **

= Voltage across (R2 + R3)

**= 4.60 volts (ANSWER).**

**So, **

** v1 = 2.30 volts **

**v2 = 1.533 volts **

**v3 = 4.067 volts **

**v4 = 4.60 volts **

**(ANSWER).**

## Conclusion

Above is the solution for “**Four resistors are connected to a battery as shown in the figure. The current in the…**“. We hope that you find a good answer and gain the knowledge about this topic of **science**.