In the diagram below, there are two charges of +q and q and six points (a through f) at various distances from the two charges
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Question “In the diagram below, there are two charges of +q and q and six points (a through f) at various distances from the two charges”
In the diagram below, there are two charges of +q and q and six points (a through f) at various distances from the two charges. Youwill be asked to rank changes in the electric potential along paths between pairs of points.
Using the diagram, rank each of the given paths on the basis of the change in electric potential. Rank the largestmagnitude positive change (increase in electricpotential) as largest and the largestmagnitude negative change (decrease in electric potential) as smallest.
Rank from largest to smallest. To rank items as equivalent, write them side by side.
a. from c to b
b. from c to d
c. from c to e
d. from d to a
e. from b to a
f. from f to e
Answer
General guidance
This question is based upon the concepts of electric potential due a charge particle, and potential difference.
Calculate the electric potential at each mark point due to each charge particle first using the general expression for electric potential. Then find the potential difference between them.
You can then compare them and write them in decreasing order.
The work needed to bring a unit of charge from infinity up to a point at electric potential is called the work. It is represented by the unit Volt, and is a scalar quantity.
The potential difference is the difference in the potential between the points. Its unit is also called volt. Twopoint A and B can have potentials V_a V_ab = V_b  V_a
HereV_ab
The equation below calculates electric potential at any point caused by charge particles.
V = \\frackQrHereV
The following formula calculates the electric potential at any given point due to a combination of charges:
V_net = V_1 + V_2 + ...V_nHere V_net
Stepbystep
Step 1 from 2
As follows:
The following can be used to calculate the electric potential at point u2018 due to positive charge:
Substitute + q V_1 = \\frackq2x
The following can be used to calculate the electric potential at point u2018 due to au2019:
Substitute  q V_2 =  \\frackq6x
Substitute\\frac{{kq}}{{2x}} \\begin{array}{c}\\\\{V_a} = \\frac{{kq}}{{2x}}  \\frac{{kq}}{{6x}}\\\\\\\\ = \\frac{{kq}}{{3x}}\\\\\\end{array}
Net potential at point u2018au2019 was\\frac{{kq}}{{3x}}
Calculate net electric potential at point \u2018b\u2019.
The electric potential at point u2018 bu2019 can be calculated using the following:
Substitute + q {V_1} = \\frac{{kq}}{x}
Add an Answer to:
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Conclusion
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