In the ground-state electron configuration of Fe3+, how many unpaired electrons are present? Express your answer…
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Question “In the ground-state electron configuration of Fe3+, how many unpaired electrons are present? Express your answer…”
In the ground-state electron configuration of Fe3+, how many unpaired electrons are present?
Express your answer numerically as aninteger.
Part B
Build the orbital diagram for the ion mostlikely formed by phosphorus.
Use the buttons at the top of thetool to add sublevels. Click within an orbital to addelectrons.
Answer
Concepts and Reason
Hund’s rule states that electrons are filled into orbitals. According to Hund’s rule, pairing electrons can only occur after all degenerate orbitals have been half-filled.
An atom that loses electrons gets a positive charge, while one that gains electrons gets a negative charge.
Fundamentals
Ground state refers to the energy state of a molecule that all electrons are present in the lowest molecular orbitals.
One electron moves from a lower energy orbital to a higher energy molecular orbital in an excited state.
A
26 is the atomic number for Fe.
To form an ion, it loses 3 electrons.
Therefore, has 23 electrons.
Its ground state electron configuration is therefore,
The orbital configuration of the outermost 3d orbital should be written as follows:
The have 5.
B
is the most likely ion to be formed by phosphorous.
The electron configuration for can be,
The orbital diagram of can be found here:
Part A – Ans
The has 5.
Part B
The orbital diagram of
can be found here:
Conclusion
Above is the solution for “In the ground-state electron configuration of Fe3+, how many unpaired electrons are present? Express your answer…“. We hope that you find a good answer and gain the knowledge about this topic of science.
has 23 electrons.
can be,
