Label all bonds in CH2Br2. Label all bonds in SO2. Label all bonds in NF3. Label…
The following solution is suggested to handle the subject “Label all bonds in CH2Br2. Label all bonds in SO2. Label all bonds in NF3. Label…“. Let’s keep an eye on the content below!
Question “Label all bonds in CH2Br2. Label all bonds in SO2. Label all bonds in NF3. Label…”
Answer
The molecule’s name is CH2Br Br Br br dibromomethane. The molecule can be described as a derivative methane. The central atom of carbon is bonded with two hydrogen atoms, and two bromine. All bonds are sigma. Below is the electron configuration for the atoms. C(6): 1s22s22p2 Br(35): [Ar]3d104s24p5
It can only form four bonds, as the valency of carbon in 4 is. Each of the bromine and hydrogen atoms can form one bond with carbon. This moecule of carbon undergoes four bonds through sp3 hybridization. Bromine uses the single electron in the p orbital to form its four bonds. Hydrogen uses it to form a sigma bond. The molecule does not contain any po bonds. Label the hybrid orbitals as follows: a) C(sp3) -Hs o: b) C(sp3) -Br (p) a) C(sp3) -Hs a) C(sp3) -Brip
Conclusion
Above is the solution for “Label all bonds in CH2Br2. Label all bonds in SO2. Label all bonds in NF3. Label…“. We hope that you find a good answer and gain the knowledge about this topic of science.