Please Help with BOTH 1) 2) A CI is desired for the true average stray-load loss…
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Question “Please Help with BOTH 1) 2) A CI is desired for the true average stray-load loss…”
Please Help with BOTH
1)
2)
A CI is desired for the true average stray-load loss u (watts) for a certain type of induction motor when the line current is held at 10 amps for a speed of 1500 rpm. Assume that stray-load loss is normally distributed with o = 2.6. (Round your answers to two decimal places.) (a) Compute a 95% CI for u when n = 25 and x = 53.0. 1 watts (b) Compute a 95% CI for u when n = 100 and x = 53.0. D ) watts (c) Compute a 99% CI for y when n = 100 and x = 53.0. D ) watts (d) Compute an 82% CI for u when n = 100 and 7 = 53.0. ) watts ( (e) How large must n be if the width of the 99% interval for u is to be 1.0? (Round your answer up to the nearest whole number.) You may need to use the appropriate table in the Appendix of Tables to answer this question.
Assume that the helium porosity (in percentage) of coal samples taken from any particular seam is normally distributed with true standard deviation 0.78. (a) Compute a 95% CI for the true average porosity of a certain seam if the average porosity for 22 specimens from the seam was 4.85. (Round your answers to two decimal places.) (b) Compute a 98% CI for true average porosity of another seam based on 16 specimens with a sample average porosity of 4.56. (Round your answers to two decimal places.) (c) How large a sample size is necessary if the width of the 95% interval is to be 0.47? (Round your answer up to the nearest whole number.) specimens (d) What sample size is necessary to estimate true average porosity to within 0.22 with 99% confidence? (Round your answer up to the nearest whole number.) specimens You may need to use the appropriate table in the Appendix of Tables to answer this question.
Answer
1) a) The critical value at 95% confidence level is z 0.25 = 1.96
The confidence interval of 95% is
b) The confidence interval of 95% is
c) The critical value at 99% confidence level is z 0.05 = 2.58
The confidence interval of 99% is
d) The critical value at 82% confidence level is z 0,09 = 1.34
The confidence interval of 82% is
e) The critical value at 99% confidence level is z 0.05 = 2.58
Margin of error = 1/2
2)a) The critical value at 95% confidence level is z 0.25 = 1.96
The confidence interval of 95% is
b) The critical value at 98% confidence level is z 0,01 = 2.33
The confidence interval of 98% is
c) Margin error = 0.47/2
d) Margin error = 0.22
t 20.025/n
2.6 53 1.96 /25
53+1.02
51.98, 54.02
t 20.025/n
2.6 53 1.96 100
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t 20.025/n
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