please show work = To cool a summer home without using a vapor-compression refrigeration cycle, air…
The following solution is suggested to handle the subject “please show work = To cool a summer home without using a vapor-compression refrigeration cycle, air…“. Let’s keep an eye on the content below!
Question “please show work = To cool a summer home without using a vapor-compression refrigeration cycle, air…”
= To cool a summer home without using a vapor-compression refrigeration cycle, air is routed through a plastic pipe (k = 0.15 W/m-K, Di -0.15 m, Do-0.17 m) with a smooth interior surface that is submerged in an adjoining body of water. The water temperature is nominally at Too = 17°C, and a convection coefficient of ho- 1500 W/m2K is maintained at the outer surface of the pipe. Air from the home enters the pipe at a temperature of Tm, 1 – 29°C and a volumetric flow rate of v’-0.05 mº/s, where a pipe length L = 20 mis needed to provide a discharge temperature of Tmo. Air Ti Tm Plastic pipe * D D Water, T (a) What is the air outlet temperature, Tm,o? What is the fan power requirement? (b) The convection coefficient associated with airflow in the pipe may be increased twofold by inserting ac Jason from WileyPLUS length of the pipe to disrupt flow conditions near the inner surface. If such a heat transfer enhancement se WileyPLUS Scheduled Mainten the attendant value of Tm,o? Use of the insert would not come without a corresponding increase in the fi As Wiley continues to fine tune What is the power requirement if the friction factor is increased by 50%? Physical Properties Mathematical Functions
Step 1 Your Answer Correct Answer What is the mean velocity of the air in the pipe, in m/s? um m/s Step 2 Your Answer Correct Answer What is the heat transfer resistance on the inside of the original pipe (without the spring), in K/W? Ri- K/w 5
Question 7 of 10 < > x Your answer is incorrect. What is the total heat transfer resistance from the air to the water for the original pipe, in K/W? R tot – 2.335 K/W Step 4 Your Answer Correct Answer What is the air outlet temperature for the original pipe, in °C? Tm, 0 = C 5
What it the pressure drop through the original pipe, in Pa? Ap= Pa Step 6 Your Answer Correct Answer X Your answer is incorrect. What is the fan power requirement for the flow through the original pipe, in W? P 0.078 w
Step 7 Your Answer Correct Answer What is the outlet air temperature for the enhanced pipe with the coil spring inserted in °C? Tm, o- °C Step 8 Your Answer Correct Answer What is the fan power requirement for the enhanced pipe with the coil spring, in W? Pas w
Answer
Solutions Given bata, Ka=0.15w/mk. Dr = 0.15m Do = 1#m. ho=1500 w/mrk. Volumetric flow rate; Te=0.05 mbls. Pipe rength’s Liom. I use a Vi-Area cross-section to calculate the mean velocity at air. 0.05 = 1.082XV. -> 0.05-4XC0.15)?xv. v=2.829umis Mean velocity. Calculate moss flow rate nape Av=P placed density fi= 1.155kg (m3. 1-155 0.05-0.05795kg (1. 1-155 0.05-0.05795 kg (1. um UxQo5p 95 TX0-15 x 183-6×107 Res 26 699.195. De moim
since; Rezuooo. The flow is turbulent. Assuming that the pipe has fully developed flow, calculate the internal coefficient of heat transport wing relation hika 0.03 Re..&pr 0.3. Di 2 12.535 W/m2K.. Calculate the inside thermal Resistance using Equation. (Rehdi = 0.0.01693 kw.ms 13. Now, Total Heat Transfer Resistance is gevens Rth=(Ret.en.Doldi.) 21TX0.15X10 OOOXX O (Rth total = 0.033434 KW).
We know 3; (Rehtotal = JX AS area. -> JAS = 0.02 0.03034 32.9651WK Specific heat = cp=1007J/kgK -0.05755 kgis asing Relation, Too-Tmio – e – TAS Too Tmi -32.9651 17-Tm, 17-29 e 17 TMO – 0.56685 > e -12 17-Tm,o=-6.8077. f = 0.316 RelyTm, = 23.8077degC 22.9751WK Tals outlet Temperature Calculate friction paeth ihing relationships 0.316 0.02472. 26699.195) “4 pressure drop inside the pipe is given in relations AP-fei Uzm, = 0.02472×1.55* (2 22942 aX0-15 140
AP= 7.6189. Calculate fan power as follows! power APX&= 7.6189 +0.05 Power 0.380950 fan power Requirement Step 1 = 2-829umis- step2 = 0.01693 kw. Step3 = 0.030344 kw. Stepu = 23.8077degC. Step 5 = 7.6isapa. Step 6 = 0.38 095w. Please like. It’s a great help!
Conclusion
Above is the solution for “please show work = To cool a summer home without using a vapor-compression refrigeration cycle, air…“. We hope that you find a good answer and gain the knowledge about this topic of engineering.