Rate Laws (Section)Consider the reaction of peroxydisulfate ion (S2O8 2-) with iodide ion (I – )…
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Question “Rate Laws (Section)Consider the reaction of peroxydisulfate ion (S2O8 2-) with iodide ion (I – )…”
Rate Laws (Section)
Consider the reaction of peroxydisulfate ion (S2O8 2-) with iodide ion (I – ) in aqueous solution:
S2O82 – (aq) + 3 I – (aq)→2 SO42 – (aq) + I3– (aq)
At a particular temperature the initial rate of disappearance of S2O8 2 – varies with reactant concentrations in the following manner:
Experiment | [S2O82‑] (M) | [I_] (M) | Initial Rate (M/S) |
1 | 0.018 | 0.036 | 2.6 × 10-6 |
2 | 0.027 | 0.036 | 3.9 × 10-6 |
3 | 0.036 | 0.054 | 7.8 × 10-6 |
4 | 0.050 | 0.072 | 1.4 × 10-5 |
(a) Determine the rate law for the reaction and state the units of the rate constant. (b) What is the average value of the rate constant for the disappearance of S2O8 2 – based on the four sets of data? (c) How is the rate of disappearance of S2O8 2 – related to the rate of disappearance of I – ? (d) What is the rate of disappearance of I – when [S2O8 2-] = 0.025 M and [I – ] = 0.050 M ?
Answer
(a)
Take a look at the following:
The following data are available to show the rate of disappearance for as well as :
Here’s how to calculate xy:
Calculate y as follows:
Write the rate expression thus:
The overall order of the reactions is 1+1=2
The overall order of the reactions is therefore 2.
Rate constants can be described as units.
are the units of constant rate.
(b)
The following formulae can be used to calculate the average rate constant value:
Experiment 1:
This experiment has a rate constant of
.
Experiment 2:
This experiment has a rate constant of
.
Experiment 3:
Therefore, the rate constant in this experiment is
.
Experiment 4:
Thus, the rate constant in this experiment is
.
Below is how to calculate the average rate constant value:
is the average rate constant.
(c)
Here is the relationship between
disappearance rate:
due to disappearance. Products are being formed by reactants.
(d)
disappears when tag33 has 0.025M and tag34 has 0.050M.
Hence,
The problem data is presented in terms of
.
Hence,
Hence,
is the rate of disappearance.
Conclusion
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