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Sam, whose mass is 75 kg , takes off across level snow on his jet-powered skis. The skis have a thrust of 160 N and a c…

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Question “Sam, whose mass is 75 kg , takes off across level snow on his jet-powered skis. The skis have a thrust of 160 N and a c…”

Sam, whose mass is 75 kg , takes off across level snow on his
jet-powered skis. The skis have a thrust of 160 N and a coefficient
of kinetic friction on snow of 0.1. Unfortunately, the skis run out
of fuel after only 15 s .

A: What is Sam’s top speed?

– I found the answer to be 17 m/s (can you check this for
me?)

B: How far has Sam traveled when he finally coasts to a stop? (I
have no idea for this one)

PLEASE HELP. AND I ONLY HAVE ONE SHOT TO PLEASE ONLY ANSWER IF
YOU TURLY KNOW

Answer

Concepts and Reason

Newton’s laws and kinematic equations are the required concepts to solve this problem.

First, use Newton’s second law to find the acceleration. Next, you can use the kinematic equations of motion to find the top speed for Sam. Next, calculate the distance traveled when fuel was available. Then, determine the distance traveled when fuel was depleted and add it to get the distance Sam has travelled.

Fundamentals

Newton’s second law states that the force applied to a body will be proportional to its acceleration.

You can write the second law of Newton as follows:


F=ma


is the force, HTMLmedia_tag_2$is mass, and HTMLmedia_tag_3$ acceleration.

The frictional force can be described as:


f = umg


f represents the frictional force,

the coefficient of friction and g the acceleration due to gravity.

These are the kinematic equations for motion.


v=u+at ul +-ar 12 -u= 2as


Here

is the initial velocity;

the final velocity;

the acceleration;

the time and

the distance traveled.


(A)

Newton’s second law states that the acceleration of the body can be,


F-f a=


to f.


a-t-img --ug


Substitute

to

;

to

;

to

;

9.8m/s2

to

.


160N -(0.1)(9.8 m/s²) 75kg = 1.15 m/s2


The kinematic equation is the motion of a body.


v=u+ at


Substitute

to

;

to

;

1.15m/s?

to

.


v=(0m/s)+(1.15m/s) (15s) = 17.25 m/s



(B)

The first distance traveled is.


ကို+in =


Substitute

to

;

to

;

to

.


si =(0m/s)(158) +-(1.15m/s?)(155) = 129.37m


The expression for Sam’s acceleration after media_tag_40$, is:


ar


to f.


811 = Suuri=,0


Substitute HTMLmedia_tag_19$ to

or HTMLmedia_tag_46$ to

.


a=(0.1)(9.8m/s?) = -0.98m/s?


Acceleration is actually a negative thing because speed is declining.

The equation of motion is:


v=u+ at


For the time it took Sam to get to sleep, rewrite the equation.


V-U 1


Substitute

to

;

17.25 m/s

to

;

-0.98m/s

to

.


--- (0m/s)-(17.25m/s) -0.98 m/s = 17.6s


Distance traveled



Substitute

0.98 m/s

for

and

for

.


s=(0.98m/s?)(17.65) = 151.8m


Sam has travelled approximately,


d=s+s


Substitute

129.37m

for

and

151.8m

for

.


d=129.37m+151.8m = 281.17 m


Part A – Ans

Sam’s top speed is

17.25m/s

Conclusion

Above is the solution for “Sam, whose mass is 75 kg , takes off across level snow on his jet-powered skis. The skis have a thrust of 160 N and a c…“. We hope that you find a good answer and gain the knowledge about this topic of science.


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