Suppose y = √(2x + 1), where x and y are functions of t.
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Question “Suppose y = √(2x + 1), where x and y are functions of t.”
Suppose y = √(2x + 1), where x and y are functions of t.
(a) If dx/dt = 3, find dy/dt when x = 4
(b) If dy/dt = 4, find dx/dt when x = 40.
Answer
Answer 1
Answer 2
. Given y= dext? ( a=4; To determine if dx = 3, ..y = 1 237) By dividing wisit” EURde = (v22+7) faa a.lux)=zinff (x)=1 CamScanner
22+ (2x+1). ___= _____(2(19+0), – 212) 2 *x = 4 )T=3_ay. / (3) kaa & TE_dy_2 __ — 40 +o , ak=? CS$canned with CamScanner
“Neng (Shi) 2x+) She ( 24+1), d = 2 (40 dt Ju) J2 40 (1) = JS1 (2) = (x=18 Jing = [18]) CamScanner
Conclusion
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