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The switch in the figure (Figure 1) has been in position a for a long time. It is changed to position b at t=0s. Par…

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Question “The switch in the figure (Figure 1) has been in position a for a long time. It is changed to position b at t=0s. Par…”

The switch in the figure (Figure 1) has been in position a for a
long time. It is changed to position b at t=0s.

The switch in the figure (Figure 1) has been in position a for a long time. It is changed to position b at t=0s. Par...

Part A

What is the charge Q on the capacitor immediately after
the switch is moved to position b?

Express your answer using two significant figures.

Q =  ?C  

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Up

Part B

What is the current I through the resistor immediately
after the switch is moved to position b?

Express your answer using two significant figures.

I =  mA  

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Up

Part C

What is the charge Q on the capacitor at
t=50?s?

Express your answer using two significant figures.

Q =  ?C  

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Up

Part D

What is the current I through the resistor at
t=50?s?

Express your answer using two significant figures.

I =  mA  

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Up

Part E

What is the charge Q on the capacitor at
t=200?s?

Express your answer using two significant figures.

Q =  ?C  

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Up

Part F

What is the current I through the resistor at
t=200?s?

Express your answer using two significant figures.

I =  mA

Answer

Concepts and Reason

This problem can be solved by charging an RC circuit.

The charge on a capacitor can initially be calculated by multiplying its capacitance and the voltage of a battery. Ohm’s law later allows you to calculate the current flowing through the circuit. The instantaneous charge of the capacitor can then be calculated by multiplying the instantaneous voltage with the capacitance.

The ratio of the instantaneous resistance to the voltage can then be used to calculate the instantaneous charge. The instantaneous charge of the capacitor can also be calculated by multiplying the instantaneous voltage with the capacitance. The ratio of the instantaneous resistance and the voltage can be used to calculate the instantaneous charge.

Fundamentals

Below is the expression for the charge of the capacitor


Q=CV


represents the voltage, #media_tag_2$ the charge and @media_tag_3$ the capacitance.

This is the expression of the circuit’s current:



is the current and

the resistance in the circuit.

Below is the expression for the instantaneous voltage


V=Vel/RC)


is the instantaneous voltage, and

represents time.

This is the expression of the instantaneous capacitor charge:


O=CV


is the instantaneous cost.

Below is the expression for the instantaneous current



is the instantaneous current.


(A)

This is the expression for the charge on a capacitor:


Q=CV


Substitute HTMLmedia_tag_15$ to

or HTMLmedia_tag_17$ to

.


e-[(2-)(103}}ov) = 18x10C 18 uc



(B)

This is the expression for current:



Substitute

for

,

for

.


I= (9.0 V) (502) = 0.18 A



(c)

This is the expression for instantaneous voltage:


V=Vel/RC)


Substitute

to

;

to

;

2.0 uF

to

;

to

.


{sousy mo V=(9.0V)|el(600](2018 months = 5.459 V


Below is the expression for an instantaneous cost.


O=CV


Substitute HTMLmedia_tag_37$ to

and HTMLmedia_tag_39$ to

.


Q=(5.459 V)|(2 uF)/ 1x10^F)] 21 = 10.918x10°C *11uC



(d)

This is the expression for instantaneous current:



Substitute HTMLmedia_tag_43$ to

or HTMLmedia_tag_45$ to

.


1- (5.459 v) (502) =0.10918 A = 109.17 mA 110 mA



(e)

This is the expression for instantaneous voltage:



Substitute

to

;

to

;

2.0 uF

to

;

2.0 uF

to

2.0 uF

;

2.0 uF

;

200 μs


(2013) $100 V=(9.0V)) el(900(2018) = 1.218 V


Below is the expression for an instantaneous cost.



Substitute HTMLmedia_tag_59$ to

or HTMLmedia_tag_61$ to

.


Q=(1218 V)|(20) LXION * 1uF ) = 2.436x10c = 2.4 uc



(f)

This is the expression for instantaneous current:



Substitute

1.218 V

,


1-(1.218 V) (502) = 0.02436 A 24 mA


Ans Part A

The charge on a capacitor is

18 με

Conclusion

Above is the solution for “The switch in the figure (Figure 1) has been in position a for a long time. It is changed to position b at t=0s. Par…“. We hope that you find a good answer and gain the knowledge about this topic of science.


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