The voltage supplied by a wall socket varies with time,reversing its polarity with a constant frequency,…
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Question “The voltage supplied by a wall socket varies with time,reversing its polarity with a constant frequency,…”
time,reversing its polarity with a constant frequency, as shown in
thegraph. (Intro 1 figure)
theresulting circuit can be represented by a simplified AC circuit,
asshown in the figure. (Part B figure) Here the lamp has been
replaced by a resistor with an equivalentresistance Part B figure)
Here the lamp has been replaced bya resistor with an equivalent
resistance = 120
.
What is the rms value of the
current flowing through the circuit?
Answer
This problem can be solved using the root square mean value for current and voltage in AC circuits.
The first part of the equation uses the relationship between {V_{rms}}
Next, use the {I_{rms}} relation
The square root of the mean value for the instantaneous value is called the root square. Mathematically, this expression can be expressed as:
{V_{rms}} = \frac{{{V_{peak}}}}{{\sqrt 2 }}The {I_{rms}} expression
{I_{rms}} = \frac{{{V_{rms}}}}{R}R here is the value for resistance.
(1)
The expression $math_tag_0
{V_{rms}} = \frac{{{V_{peak}}}}{{\sqrt 2 }}Substitute 170 V to {V_{peak}} \begin{array}{c}\\{V_{rms}} = \frac{{170{\rm{ volts}}}}{{\sqrt 2 }}\\\\ = 120.21{\rm{ volts}}\\\end{array}
(2)
Substitute 120.21 Volts for V or 120\Omega
$math_tag_10
Part 2: The {V_{rms}} value
The flowing current’s rms value is 1.0 A.
Conclusion
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