**Two long thin parallel wires 13.0cmapart carry 35 Acurrents in the same direction….**

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## Question “Two long thin parallel wires 13.0cmapart carry 35 Acurrents in the same direction….”

Two long thin parallel wires 13.0cmapart carry 35 A

currents in the same direction.Determine the magnetic field vector at a point

10.0 cmfrom one wire and 6.0 cmfrom the other.

13.0 cm 10,0 cm 10.0 cm +

## Answer

To calculate the magnetic force at point P, use the expression for magnetic field due wire.

refers to the permeability free space. *I* represents the current through the wire. *r* indicates the distance between the wire and the point P.

The following illustration shows the magnetic fields generated by the two wires at P.

represents the current produced from the wire 1, while

represents the current produced at the wire 2.

refers to the magnetic force due to wire 1.

refers to the magnetic fields due to wire 2.

describes the angle created by magnetic field

along the line connecting the two wires.

indicates the angle made magnetically by

by the line joining them.

The law of cosines states that the cosine determined by angle created by magnetic field vector 1 is the angle, according to,

indicates the distance between the wires.

shows the distance from wire 1 to point P.

shows the distance between wire 2 and point P.

for the above equation. Add 6 cm

to this equation.

The law of cosines states that the cosine (angle made by magnetic field vector created by wire 2) is the cosine.

indicates the distance between the wires.

represents the distance from wire 1 to point P.

signifies the distance between wire 2 and point P.

. Then solve the equation as follows:

The magnetic field due wire 1 is described by

Substitute HTMLmedia_tag_28$ to

; 35 A for #media_tag_30$; and 10 cm for

as follows:

The magnetic field vector due wire 1 is given below.

As follows:

The magnetic field caused by wire 2 is calculated by

Substitute HTMLmedia_tag_40$ to

; 35 A for #media_tag_42$; and 6 cm in the above equation for

:

The magnetic field vector due wire 2 is given below.

In the above equation, substitute

for #media_tag_49$

The net magnetic field at P is calculated by

In the above equation, substitute

for #media_tag_55$

.

The magnitude of the net magnet field is calculated by

refers to the *x* component of the magnetic magnetic field, and

refers to the *y*– part of the magnetic magnetic field.

In the above equation, substitute

for #media_tag_64$

The magnitude of the magnetic force at point P is therefore

.

The magnetic field direction is determined by

Substitute HTMLmedia_tag_68$ to

or HTMLmedia_tag_70$ to

as follows:

The magnitude of the magnetic force at P is

, and it is directed at an angle

**higher than the horizontal**.

## Conclusion

Above is the solution for “**Two long thin parallel wires 13.0cmapart carry 35 Acurrents in the same direction….**“. We hope that you find a good answer and gain the knowledge about this topic of **science**.