Using values from Appendix C in the textbook, calculate the standard enthalpy change for each of…

The following solution is suggested to handle the subject “Using values from Appendix C in the textbook, calculate the standard enthalpy change for each of…“. Let’s keep an eye on the content below!

Question “Using values from Appendix C in the textbook, calculate the standard enthalpy change for each of…”

Answer

(1.) (1.)

Standard enthalpy,

Ho =

Hö products –

Haus reactants

Ho =

Hof So3 (g), – [2*

Hof S2 (g), +

Hof o2 (g),]

H^o = 2 * (-395.2 kJ/mol) – [2 * (-296.9 kJ/mol) + (0)]

H = +790.4 kJ + 5933.8 kJ

H = 196.6 kJ

(2.) (2.)

Standard enthalpy,

Ho =

Hö products –

Haus reactants

Ho =

Hof H2O (s), +

Hof H2O (l),] –

Mg(OH),2 (s).

H^o = [(-601.8 kJ/mol) + (-285.83 kJ/mol)] – (-924.7 kJ/mol)

H = 887.63 kJ + 9244.7 kJ

H = 37.07 KJ

(3.) (3.)

Standard enthalpy,

Ho =

Hö products –

Haus reactants

Ho =

HofN2(g), + 4 *

H2O (g),] –

HofN2O4(g), + 4 *

H2O(g),]

H^o = [(0) + 4 * (-241.82 kJ/mol)] – [9.66 kJ/mol + 4 * (0)]

H = 967.28 kJ- 9.66 kJ

H = 976.94 KJ

Q4. Q4.

Standard enthalpy,

Ho =

Hö products –

Haus reactants

Hof SIO2(s), + 4 *

HCl(g),] – [

Hof siCl4(l), + 2 *

H2O(l),]

H^o = [(-910.9 kJ/mol) + 4 * (-92.30 kJ/mol)] – [(-640.1 kJ/mol) + 2 * (-285.83 kJ/mol)]

H = 1280.1 kJ + 12011.76 kJ

H = +68.34 KJ

Conclusion

Above is the solution for “Using values from Appendix C in the textbook, calculate the standard enthalpy change for each of…“. We hope that you find a good answer and gain the knowledge about this topic of science.