Using values from Appendix C in the textbook, calculate the standard enthalpy change for each of…
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Question “Using values from Appendix C in the textbook, calculate the standard enthalpy change for each of…”
Using values from Appendix C in the textbook, calculate the
standard enthalpy change for each of the following reactions.
Link to Appendix C:
https://media.pearsoncmg.com/ph/esm/esm_brown_chemistry_14/appendices/appendix-c.pdf
1. 2SO2(g)+O2(g)→2SO3(g)
2. Mg(OH)2(s)→MgO(s)+H2O(l)
3. N2O4(g)+4H2(g)→N2(g)+4H2O(g)N2O4(g)+4H2(g)→N2(g)+4H2O(g)
4. SiCl4(l)+2H2O(l)→SiO2(s)+4HCl(g)
Answer
(1.) (1.)
Standard enthalpy,

Ho =

Hö products –

Haus reactants
Ho =

Hof So3 (g), – [2*

Hof S2 (g), +

Hof o2 (g),]

Ho = 2 * (-395.2 kJ/mol) – [2 * (-296.9 kJ/mol) + (0)]

H = +790.4 kJ + 5933.8 kJ

H = 196.6 kJ
(2.) (2.)
Standard enthalpy,

Ho =

Hö products –

Haus reactants
Ho =

Hof H2O (s), +

Hof H2O (l),] –

Mg(OH),2 (s).

Ho = [(-601.8 kJ/mol) + (-285.83 kJ/mol)] – (-924.7 kJ/mol)

H = 887.63 kJ + 9244.7 kJ

H = 37.07 KJ
(3.) (3.)
Standard enthalpy,

Ho =

Hö products –

Haus reactants
Ho =

HofN2(g), + 4 *

H2O (g),] –

HofN2O4(g), + 4 *

H2O(g),]

Ho = [(0) + 4 * (-241.82 kJ/mol)] – [9.66 kJ/mol + 4 * (0)]

H = 967.28 kJ- 9.66 kJ

H = 976.94 KJ
Q4. Q4.
Standard enthalpy,

Ho =

Hö products –

Haus reactants
Hof SIO2(s), + 4 *

HCl(g),] – [

Hof siCl4(l), + 2 *

H2O(l),]

Ho = [(-910.9 kJ/mol) + 4 * (-92.30 kJ/mol)] – [(-640.1 kJ/mol) + 2 * (-285.83 kJ/mol)]

H = 1280.1 kJ + 12011.76 kJ

H = +68.34 KJ
Conclusion
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