What is the molar solubility of Mg(OH)2 in a basic solution with a pH of 12.00? Ksp for Mg(OH)2 is 5.6 × 10-12.
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Question “What is the molar solubility of Mg(OH)2 in a basic solution with a pH of 12.00? Ksp for Mg(OH)2 is 5.6 × 10-12.”
pH of 12.00? Ksp for
Mg(OH)2 is 5.6 × 10-12.
Answer
Molar solubility refers to the amount of compound or substance that can be dissolved in a liter of solution. It is dependent on the stoichiometry and can be found by the solubility products constant. The pH value is the concentration of hydrogen ions in a solution. It indicates whether the solution is acidic or basic. Solution with a high concentration of hydrogenions will have a lower pH value, while solutions with fewer hydrogen ions will have a higher pH value. Solutions with high pH values are more acidic.
Solubility product constant and molar solubility are calculated using the concentration of a compound reaction.
2-in-a-basic-solution-with-a-pH-of-12.00?-Ksp-for-Mg(OH)2-is-5.6-×-10-12..png?x-oss-process=image/resize,w_560/format,webp)
![Ksp =[X][Y]
where, Y = xso, X = 2x](https://drive.google.com/uc?id=1S-idNpesTF8hS3k9hdCsUCRG67TJJXBR&export=download/What-is-the-molar-solubility-of-Mg(OH)2-in-a-basic-solution-with-a-pH-of-12.00?-Ksp-for-Mg(OH)2-is-5.6-×-10-12..png?x-oss-process=image/resize,w_560/format,webp)
We can now find x, which is the molar solubility for that compound.
2-in-a-basic-solution-with-a-pH-of-12.00?-Ksp-for-Mg(OH)2-is-5.6-×-10-12..png?x-oss-process=image/resize,w_560/format,webp)
and _media_tag_4$
2-in-a-basic-solution-with-a-pH-of-12.00?-Ksp-for-Mg(OH)2-is-5.6-×-10-12..png?x-oss-process=image/resize,w_560/format,webp)
pH = 12
pOH = 14-12 = 2.
![pOH = 14 -12 = 2
[OH-]=10 2 = 0.01M](https://drive.google.com/uc?id=1Ih6gE_u1DJALRHM8MDI_jiLgyU298lnC&export=download/What-is-the-molar-solubility-of-Mg(OH)2-in-a-basic-solution-with-a-pH-of-12.00?-Ksp-for-Mg(OH)2-is-5.6-×-10-12..png?x-oss-process=image/resize,w_560/format,webp)
So,
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Initial | – | 0 | 0.01 M | |
Change | – | x | 2x+0.01M | |
At equilibrium | – | x | 2x+0.01M |
Expression of a Solubility Product:
![[OH-]=102 = 0.01M
K. = [Mg2+ ][20H-1
K =[x][2x+0,01M ]
2x <<0.01M so, 2x can be neglected
K =[x][0.0001]
5.6x10-12 /0.0001 =](https://drive.google.com/uc?id=1ersaco4zjTkin9EluEi9riIBFV4brkIy&export=download/What-is-the-molar-solubility-of-Mg(OH)2-in-a-basic-solution-with-a-pH-of-12.00?-Ksp-for-Mg(OH)2-is-5.6-×-10-12..png?x-oss-process=image/resize,w_560/format,webp)
Ans:
2-in-a-basic-solution-with-a-pH-of-12.00?-Ksp-for-Mg(OH)2-is-5.6-×-10-12..png?x-oss-process=image/resize,w_560/format,webp)
=
2-in-a-basic-solution-with-a-pH-of-12.00?-Ksp-for-Mg(OH)2-is-5.6-×-10-12..png?x-oss-process=image/resize,w_560/format,webp)
Conclusion
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