1. Draw Lewis Dot structures for the following: a. O b. Ge c. S-2 d. CO2 e. NF3 f. CC14
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Question “1. Draw Lewis Dot structures for the following: a. O b. Ge c. S-2 d. CO2 e. NF3 f. CC14”
Answer
Ans) Lewis dots structures show bonding between atoms of a molecular and the arrangement electrons around individual molecules.
a) Oxygen is composed of 6 valence electrons. We write the symbol of oxygen with 6 dots and then add
b).
Germanium, Ge is a member of group 14 and has four valence electrons. The lewis dot structure for Ge is therefore
c) S2–
Sulphur is a member of group 16. It has 6 valence electrons. Sulphide, S2 – has an electron charge of -2 which means it has gained two electrons. Its lewis dot structure can be described as follows:
d) CO2
There are 4 valence electrons in carbon and 6 for oxygen. It is necessary to arrange electrons so that each atom’s octet is complete. The lewis dot structure can be described as
e) NF3
Flourine contains 7 valence electrons, while Nitrogen has 5. The lewis dot structure for NF 3 is
f) CCl4
Carbon has four valence electrons, while Chlorine has seven. The lewis dot structure for CCl4 can be found here
Conclusion
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