2: Resonance Structures
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Question “2: Resonance Structures”
For each resonance atructureuse curved arrows to show the delocalization of electron pairs that transforms the structure into the next one (to the right) .
Answer
Answer 1
It is necessary to show the curved arrow mechanism of a compound in order to determine the resonance structure. The \pi delocalization creates resonance structures.
* The delocalization $math_tag_0 can help to create a resonance structure
The delocalization $math_tag_0
Take a look at the following illustration to see the resonance structure created by the delocalization of the lone bond and the double bond. It is illustrated by curving arrows.
![ܕܘܝܺ](https://drive.google.com/uc?id=11bZklWIMkwGwP6_HJ43FLSYBUC2oM4a6&export=download/2:-Resonance-Structures.png?x-oss-process=image/resize,w_560/format,webp)
An arrow generally starts with a nucleophile, and ends at an electrophile, showing the attack. This is where electron density changes from high to low. The electron density is taken by a leaving group.
The direction of an arrow represents the movement of electrons, as shown below.
![Η.
Ce
+
CH
electron deficient
species
Electron rich
species](https://drive.google.com/uc?id=1yaunduEw1I6xvA2otQopjunZSAbLhyrB&export=download/2:-Resonance-Structures.png?x-oss-process=image/resize,w_560/format,webp)
The curved arrows are used to demonstrate the conversion of the first resonance structure into the second, without altering any charges.
![(II)](https://drive.google.com/uc?id=1C_h6sgjybjknonbJUL9oT7UchFsvmZyV&export=download/2:-Resonance-Structures.png?x-oss-process=image/resize,w_560/format,webp)
The curved arrows can be used to demonstrate the conversion of the second resonance structure into the third, without changing any charges.
![NH
(11)](https://drive.google.com/uc?id=1p0KLneSquYZLyegjYZ4ZiLik25QXfKYG&export=download/2:-Resonance-Structures.png?x-oss-process=image/resize,w_560/format,webp)
The curved arrows can be used to demonstrate the conversion of the third resonance structure into the fourth, without changing any charges.
![](https://drive.google.com/uc?id=1_8kHENFiOsWD1m0b3L3NSJK9Wh5GRiPo&export=download/2:-Resonance-Structures.png?x-oss-process=image/resize,w_560/format,webp)
To show how the fourth resonance structure is converted, use the curved arrows. This will allow you to restore the original structure with no formal charges.
![“ΗΝ](https://drive.google.com/uc?id=1e7Za9hSd0llbScNt6_Dt9ChdF_UL1SUc&export=download/2:-Resonance-Structures.png?x-oss-process=image/resize,w_560/format,webp)
Ans:
The following curved arrows can be used to show the delocalization electrons in order to form the resonance structures.
![NH
(11)
(IV)](https://drive.google.com/uc?id=1BoqZPm3tOPt7MbLJIyqJ5d9f3tMJn5lS&export=download/2:-Resonance-Structures.png?x-oss-process=image/resize,w_560/format,webp)
Answer 2
![2: Resonance Structures](https://drive.google.com/uc?id=1z7VZp7mHJhGVauRVLqEfeAdsMshQdK3O&export=download/2:-Resonance-Structures.png?x-oss-process=image/resize,w_560/format,webp)
Conclusion
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