A balloon vendor at a street fair is using a tank of helium to fill her balloons. The tank has a volume of 160.0 L and a…
The following solution is suggested to handle the subject “A balloon vendor at a street fair is using a tank of helium to fill her balloons. The tank has a volume of 160.0 L and a…“. Let’s keep an eye on the content below!
Question “A balloon vendor at a street fair is using a tank of helium to fill her balloons. The tank has a volume of 160.0 L and a…”
A balloon vendor at a street fair is using a tank of helium to
fill her balloons. The tank has a volume of 160.0 L and a pressure
of 109.0 atm at 25.0 °C. After a while she notices that the valve
has not been closed properly. The pressure had dropped to 99.0 atm.
(The tank is still at 25.0 °C.) How many moles of gas has she
lost?
Answer
Answer-
Given,
Volume of Helium Tank = 160.0 Liters
Initial Pressure (P1) in Tank = 109.0 atm
Final Pressure (P2) in Tank = 99.0 atm
Temperature of Tank = 25 C, or 298.15K [0degC+ 273.15 = 273.15K]
Moles that have been lost because of leakage =
That is what we know.
PV = nRT
where,
P = Pressure
V = Volume
T = Temperature
n = Moles
R = Gas Constant (0.08206 Latmmol-1K-1)
So,
n = PV/RT
Initial moles (n1) = (P1*V)/(RT)
Final moles (n2) =(P2*V/(RT).
Moles lost = Initial moles – Final Moles
Moles lost = (P1*V)/(RT) – (P2*V)/(RT)
Moles lost = (P1 – P2) * [V/(RT)]
Place the values.
Moles lost = (109.0 atm – 99.0 atm) * [160.0 L /(0.08206 Latmmol-1K-1 * 298.15 K)]
Moles lost = 65.4 mol [Answer]
Conclusion
Above is the solution for “A balloon vendor at a street fair is using a tank of helium to fill her balloons. The tank has a volume of 160.0 L and a…“. We hope that you find a good answer and gain the knowledge about this topic of science.