A light ray is incident on a glass cylinder (n = 1.5) of radius R, at…
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Question “A light ray is incident on a glass cylinder (n = 1.5) of radius R, at…”
A light ray is incident on a glass cylinder (n = 1.5) of radius
R, at a height R/2 above an optical axis that
goes through the center of the cylinder. a. What is the angle of
incidence of the light ray on the glass cylinder in degrees
(~30)? b. What is the transmitted angle of the ray into
the glass in degrees (~19)? c. Through what angle
does the ray bend in degrees? No figure was
given.
Answer
Answer 1
(a) Let’s consider the angle of incidence
so,
—————————————————————————
(b) We can use snell’s law here
indicates angle of transmission
so,
———————————————————————–
(c) At what angle does the light ray bend ????? This question isn’t clear
What does bend mean? ?
If it refers to the angle at which light rays have deviated from their original path, it should be the same as part (b).
Answer 2
This figure will assist you in answering part c.
Snell’s law can be used because the angle of incidence for 30 degrees is.
sin(th) = n*sin(th – a)
0.5 = n*sin(30 – a)
sin(30 – a) = 0.5/n
n = 1.5
a = 30-arcsin(0.5/1.5).
a = 10.529 degrees
Conclusion
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