A transverse harmonic wave travels on a rope according to the following expression: y(x,t) = 0.14sin(2.3x…
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Question “A transverse harmonic wave travels on a rope according to the following expression: y(x,t) = 0.14sin(2.3x…”
A transverse harmonic wave travels on a rope according
to the following expression:
y(x,t) = 0.14sin(2.3x + 17.8t)
The mass density of the rope is μ = 0.107 kg/m. x and y are
measured in meters and t in seconds.
I’m missing 6, 7 and 8
1)
What is the amplitude of the
wave? 0.14m
2)
What is the frequency of oscillation of the
wave? 2.8334Hz
3)
What is the wavelength of the
wave? 2.73m
4)
What is the speed of the wave? 7.74m/s
5)
What is the tension in the rope? 6.41N
6)
At x = 3.5 m and t = 0.4 s, what is the velocity of
the rope? (watch your sign)_____ m/s
7)
At x = 3.5 m and t = 0.4 s, what is the acceleration
of the rope? (watch your sign) ______m/s2
8)
What is the average speed of the rope during one
complete oscillation of the rope?