A sinusoidal transverse wave travels along a long, stretched string. The amplitude of this wave is…
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Question “A sinusoidal transverse wave travels along a long, stretched string. The amplitude of this wave is…”
Answer
Part A.
A complete wave is the distance between maximum wave and minimum wave.
Given that the wavelength is 1.75 m
The shortest transverse distance = 1.75/2 = 0.7875 m
Part B.
Given the frequency of wave = 2.69Hz = 2.69 cycles/sec
The time needed for 51.5 cycles is:
t = N/f = 51.5 cycles/(2.69 cycles/sec) = 51.5/2.69
t = 9.1 sec
Part C.
We know that wavelength is the distance between two maximums.
Wavelength = 1.75m/cycle
String length = 31.3m
So,
N = 31.3/(1.75 m/cycle) = 17.9 cycles
Conclusion
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