Construct a confidence interval of the population proportion at the given level of confidence. x =…
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Question “Construct a confidence interval of the population proportion at the given level of confidence. x =…”
Construct a confidence interval of the population proportion at the given level of confidence. x = 860, n= 1100, 95% confidence Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2). The lower bound of the confidence interval is (Round to three decimal places as needed.) The upper bound of the confidence interval is (Round to three decimal places as needed.)
Answer
Answer 1
Sample size = n = 1100 Sample number of events = x = 860 Sample proportion = p = x/n = (860/1100) = 0.7818 (point estimate of population proportion) (1-0) Stanadard Error = = sqrt(0.7818*(1-0.7818)/1100) = 0.0125 n Confidence Level = 95 Significance Level = a = (100-95)% = 0.05 Critical value = z* = 1.96 [Using Excel =ABS(NORMINV(0.05/2,0,1))] Margin of Error = z* (standard error )= 1.96*0.0125 = 0.0244 Lower Limit =P – Margin of Error = 0.7818 -0.0244 = 0.757 Upper Limit =p + Margin of Error = 0.7818 +0.0244 = 0.806
Conclusion
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