Draw the molecular orbital diagram shown to determine which of the following is paramagnetic. N22+ B22+…
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Question “Draw the molecular orbital diagram shown to determine which of the following is paramagnetic. N22+ B22+…”
Draw the molecular orbital diagram shown to determine which of the
following is paramagnetic.
N22+
B22+
B22-
B2
C22-
following is paramagnetic.
N22+
B22+
B22-
B2
C22-
Answer
The electronic configuration of nitrogen is N (7). 1s’2s2p Nitrogen contains five valence electrons. Two electrons are in the 2s orbital, and three electrons in the 2p orbitals. Therefore, N, molecule contains 10 valence electrons. Two electrons from N,2ion will be removed. Thus, the total number of valence ions in the ion is 8. These electrons will be filled in the molecular orbitals shown in the MO diagram following Hund’s rule. Hund’s rule states electrons will only occupy two or more orbitals with equal energy if they are available before pairing. The MO diagram for N2 is: s2px-p2py 1-t 2 p. . o2p, .. T2p n2p
s2s2s o2s Atomic orbitals N N22-ar orbitals have paired electrons. Therefore, N”is diamagnetic.
Below is the electronic confluence of boron. B(5): 1s22s22p Boron contains 3 valence electrons. Six valence electrons are found in the B2 molecule. Two valence electrons are removed during the formation of B2. The B22+ ion therefore has four valence electrons. The molecular orbitals will be enriched with the valence electrons in the formation of B2. According to Hunds’s rule, Bion contains 8 valence electrons. Hund’s rule states electrons will only occupy two or more orbitals with equal energy if they are available before pairing. The MO diagram of valence orbitals is drawn. The MO diagram for B2 is T2py, t2pz, s2px and s2s 2.
Atomic orbitals for B Molecular orbitals for Atomic orbitals For B2 Molecular orbitals for Atomic orbitals For B2 Two unpaired electrons are in p2P. and p2P. molecular orbitals. It is paramagnetic because it has unpaired electrons.
MO diagram for B2 is: s2px Zs 2s o2s Molecular orbitals of Atomic orbitals. B. The molecular orbitals do not have unpaired electrons. Therefore, the ion is diamagnetic. Thus, B* is diamagnetic by nature.
MO diagram for B2is: o2p s2px and p2py Molecular orbitals 4 2s Atomic orbitals B Atomic orbitals B Molecular orbitals Of The molecular orbitals are made up of no unpaired electrons. The MOT pairs all electrons. The ion is therefore diamagnetic
C(6): 1s 2s22 2p2 The valence electrons of carbon have 4 There are 8 valence electrons in total C2 molecules. C2 will form when 2 valence electrons are added to the MO orbitals. C22ion therefore has 10 valence electrons. The MO diagram of Cis is as follows: 6’2ps, s2px2s 2s 2s C Molecular orbitals C 2 Atomic orbitals C 2 The molecular orbitals do not have unpaired electrons. C2 therefore is diamagnetic
Conclusion
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