Three identical light bulbs are connected to two batteries as shown in the diagram above.
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Question “Three identical light bulbs are connected to two batteries as shown in the diagram above.”
Three identical light bulbs are connected to two batteries as shown in the diagram above.
To start the analysis of this circuit you must write energy conservation (loop) equations. Each equation must involve around-trip path that begins and ends at the same location. Each segment of the path should go through a wire, a bulb, or a battery(not through the air). How many valid energy conservation (loop)equations is it possible to write for this circuit?
It is alsonecessary to write charge conservation equations (node) equations.Each such equation must relate electron current flowing into anodeto electron current flowing out of a node. Which of the followingare valid charge conservation equations for this circuit?
Each battery hasan emf of 1.3 volts. Thelength of thetungsten filament in each bulb is 0.015 m. The radius of the filament is 5e-6 m (itis very thin!). The electron mobility of tungsten is1.8e-3(m/s)/(V/m). Tungsten has 6e+28 mobile electrons per cubicmeter.
Since there are three unknown quantities, we need three equationsrelating these quantities. Use any two valid energy conservationequations and one validcharge conservation equation to solve forthe following electric field magnitudes:
What is the magnitude of the electric field inside bulb #1?
E1 =V/m
What is the magnitude of the electric field inside bulb #2?
E2 =V/m
How many electrons per second enter bulb #1?
i1 =electrons/s
How many electrons per second enter bulb #2?
i2 =electrons/s
Answer
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