1) Predict the product of the reaction of 1-butene with bromine (The IUPAC name) 2) An…
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Question “1) Predict the product of the reaction of 1-butene with bromine (The IUPAC name) 2) An…”
1) Predict the product of the reaction of 1-butene with bromine
(The IUPAC name)
2) An alkyne undergoes hydrogenation to produce an alkene as
follows: RC(triple bond)CR +H2 (Pd catalyst) alkene predict the
product.
3) Predict the ester product of the following reaction: CH3OH +
CH3CH2CH2COOH (H2SO4) PRODUCT + H20 (Express your answer using the
IUPAC name)
4) Predict the carboxylic acid product of the following
reaction: CH3COOCH2CH3 + H20 (H+) carbxylic acid + CH3CH2OH
(Express your answer using the IUPAC name
Answer
This question can be solved by predicting the products of the given reaction, and then writing the IUPAC names of those products. The first reaction results in dibromo products by the addition of bromine to alkene. The second reaction involves hydrogenating alkyne using $math_tag_0
1) Alkenes are hydrocarbons that have at least one double bond. Alkenes can also be involved in additional reactions due to \pi
2) Alkynes are hydrocarbons that have at least one triple bond. Alkynes undergo hydrogenation reactions when they react with hydrogen gas and palladium catalyst. This results in saturated hydrocarbons, called alkanes.
3) Carboxylic acids are organic compounds that have a carboxylic acid functional groups (-COOH), and alcohols are organic compounds with an alcohol functional group. The esterification reaction occurs when carboxylic acid reacts in the presence of an acid to produce the corresponding ester. During esterification, water molecules are eliminated.
IUPAC Nomenclature It is important to know the basic rules for assigning the names of compounds. These are the rules:
1. Identify the longest chain (parent) in the compound. It can be either a continuous or a ring.
2. Name and identify the functional groups and side chain that are attached to this particular chain.
3. Identify multiple bonds (double/triple bonds).
4. Numinate the chain so that the number of substituents is the lowest.
5. Each substituent should be identified by a number and a name.
6. When more than one type is present, the prefixes di and tri are used. These are not considered for alphabetizing.
7. Use full name to assemble the names and groups alphabetically.
1)
1.butene is the starting material. The structure of 1-butene can be seen below.
It is evident from the structure that there is one double bond, and that it is an alkene.
Discussion in the fundamental section reveals that alkene reacts with bromine molecule to produce dibromo product.
The reaction of 1-butene with the bromine molecule results in 1,2-dibromo. Below is the structure of the product as a result of the reaction.
The longest chain in the product’s structure has 4 carbons. Therefore, the parent carbon chain of butane is it. Number the chain so that the substituents have the lowest number possible. Two bromo substitutes will get 1 position and 2 position, respectively. Next, use parent name to assemble name and substitutes in alphabetical order. 1,2-dibromobutane is the IUPAC product name.
2)
The alkyne, the starting material, is shown below.
It is evident from the structure that there is one triple bond.
Alkynes undergo hydrogenation reaction upon reaction with hydrogen in the presence of palladium catalyst. This is what we discuss in the fundamental section.
The given alkyne reacts with hydrogen gas and the Pd catalyst to produce alkane. Two moles of hydrogen gas are involved in this reaction. Below is the structure of the product as a result of this reaction.
3)
These are the condensed formulas for the starting materials:
The first of the two compounds is alcohol, and the second is carboxylic acid.
As discussed in the fundamental section, carboxylic acids react with alcohols in the presence of acid to produce an ester.
By removing water molecules, butanoic acid reacts to methanol and produces methyl ester. Below is the structure of the product as a result of this reaction.
The longest chain in the product’s structure has 4 carbons. Therefore, the parent carbon chain of butane is also 4-carbon. The product’s functional group is ester, and it is methyl ester. The product’s functional group is ester and it is methyl ester.
Part 1: Ans
The product resulting from the reaction of 1-butene and bromine is 1,2-bromobutane. Its structure is shown below.
Part 2
Alkane is formed from the reaction of alkyne and hydrogen gas in the presence palladium catalyst. The structure is shown below.
Part 3
Below is the structure of an ester product formed from the reaction of given carboxylic acids with alcohol.
Conclusion
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