2) Balance C4H10 + O2 → CO2 + H2O & solve: a) If 7.54 mol of…
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Question “2) Balance C4H10 + O2 → CO2 + H2O & solve: a) If 7.54 mol of…”
2) Balance C4H10 + O2 → CO2 + H2O & solve:
a) If 7.54 mol of CO2 are produced, how many moles of O2
reacted?
b)If 9.75 kg of H2O are produced, how many moles of C4H10
reacted?
c) If 3.4500 moles of O2 react, how many grams of CO2 are
produced?
d)If 520.30 grams of C4H10 react, how many mg of H2O are
produced?
e) If 4.28 mol H2O are produced, how many molecules of O2
reacted?
Answer
2)
A balanced equation is
4 CO2 + 5 H2O
A) Mole ratio of O2 and CO2 = 4: 6.5
then ,
When 7.54 mol CO2 has been formed, moles of O2 react
= 12.25 mole
b)
9.75 Kg H2O = 9.75 Media_tag_1$ 1,000 = 9750 g
Moles of water
= ( 9750/18)
= 541.66
Now, mole ratios of H2O to C4H10
= 5 : 1
then , moles of C4H10 reacted = (541.66/5) =
108.33
c)
4:6.5 Mole ratio of O2 and CO2 = 4.
When 3.45 moles O2 were reacted, moles of carbon dioxide formed
= 2.12
Then, the grams of CO2 formed = moles
Moles molar masses = 2.12 (mol),
44 (g/mol), = 93.28 g
d)
C4H10 Molar Mass = 58g/mol
Balanced reaction
18 = 90 g water
Then, C4H10 reacts with give at 520.30g
520.30
( _media_tag_10$ _) g water
= 807.362g water
= (807.362 $1media_tag_1$ 1,000) mg water
= 807362 mg water .
e)
mole ratio of O2 and water
= 5 : 6.5
The 4.28 g of water becomes O2 moles.
= 5.56 mole O2
Now, 1 mole of oxygen has6.02 #media_tag_1$ 11 23 number
The O2 molecules reacted accordingly
5.56
1024
Conclusion
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