ALEKS Chemistry O ENTROPY AND FREE ENERGY Calculating reaction free energy under nonstandard conditions A chemist…
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Question “ALEKS Chemistry O ENTROPY AND FREE ENERGY Calculating reaction free energy under nonstandard conditions A chemist…”
ALEKS Chemistry O ENTROPY AND FREE ENERGY Calculating reaction free energy under nonstandard conditions A chemist fills a reaction vessel with 0.546 atm nitrogen monoxide (NO) gas, 1.48 atm chlorine (CI) gas, and 4.56 atm nitrosyl chloride (NOCI) gas at a temperature of 25.0°C. Under these conditions, calculate the reaction free energy AG for the following chemical reaction: 2NO(g) +C12(e) – 2NOCI(8) Use the thermodynamic information in the ALEKS Data tab. Round your answer to the nearest kilojoule. х 5 ?
emistry substance sº (J/mol-K) AH,° (kJ/mol) AGº (kJ/mol Aluminum -485.0 A13+ (aq) — 0 Al(s) Al2O3 (s) Al(OH)3 (s) 0 -1675.7 28.3 50.9 – 1582.3 – 1147.25 Bromine -104.0 0 0 152.2 Br(aq) Br2 (1) Br2 (9) HBr (9) 30.9 3.1 245.5 -36.3 -53.4 198.7 Calcium Ca2+ (aq) -553.6 CaCl2 (s) -795.4 CaO (s) -634.9 Ca(OH)2 (s) -985.2 Ca3(PO4)2 (s) -3884.7 scgi/sl.exe/IwnSn BBnyTeakW 700mQKKKQ5yIX 5aVobwlF21Gpal6oogtroFckCeD8-Va-xxvp3RAOreoJmdus MacBook Air F2 BO 000 F3 000 F4
nistry — D001./ Cu304/2 ) Carbon C(s) 0 0 5.7 CC14 (9) -95.7 -64.0 309.4 CCIA (1) -128.2 -68.6 214.4 CCIA (s) -136.8 CH4 (9) -74.6 -50.5 186.3 C2H2 (9) 227.4 C2H6 (9) -84.0 C3H8 (9) -103.85 -23.4 270.3 CaH10 (9) -125.7 -15.7 310.0 C4H10 (1) -147.3 -15.0 231.0 CGHG (1) 49.1 124.5 173.4 C. Ho (9) 82.9 129.7 269.2 Снзон (1) -239.2 -166.6 126.80 CH3OH (9) -201.0 -162.3 239.9 (CH3)2(CH2)20 (1) -279.5 -346.74 253.5 CH.06 (s) -1237.3 -910.4 itx/sl.exe/IwnSun BBOTE W700mQKKKQ5yX 5a VoblF2IGpa boogtroFckCeD8-Va-xxvP3RAOreojmdu 212.1 MacBook Air
emistry Cl2 (9) 0 0 223.1 Cl- (aq) – 131.2 HCI (aq) – 167. HCI (9) -92.3 -95.3 186.9 Chromium Cro 2- (aq) -727.8 Fluorine F2 (9) 0 0 202.8 HF (9) -273.3 -275.4 173.8 Hydrogen H2 (9) 0 0 130.7 Iron Fe (5) 0 0 27.3 FeCl3 (s) -399.5 -334.0 142.3 Fe203 (s) -824.2 -742.2 87.4 Lead -24.4 PbBr (s) -2.78.7 cgi/x/sl.exe/insun BBIVTE akW 700mQKKKQ5yIX 5aVobwlF21Gpd GoogtroFckCeD8-Va-xxvp3RAOreo mdusw -261.9 161.5 Pb2+ (aq) MacBook Air
le/content/798394/fullscreen/4577602/View PaperCut Login fo… ALEKS Chemistry… nistry Nitrogen N2 (9) 0 0 191.6 NzH4 (9) 95.4 159.4 238.5 N2H4 (1) 50.6 149.3 121.2 NH3 (9) -45.9 – 16.4 192.8 NH3 (1) -69.54 -26.50 95.09 NH4NO3 (s) -365.6 -183.9 151.1 NO (9) 91.3 87.6 210.8 NO2 (9) 33.2 51.3 240.1 NOCI (9) 51.7 66.1 261.7 N204 (9) 11.1 99.8 304.4 HNO2 (9) -79.5 HNO3 (1) -174,1 -80.7 155.6 HNO3 (9) -133.9 -73.5 266.9 Oxygen OH(aq) -157.2 H20 (1) -285.8 -237.1 70.0 Hoo (a) -241.8 Xilsl.exe/IwnSJn BBOUTEаkW 700mQKKKO5yIX 5aVobwlF210pdboogtroFckCeD8-Va-xxvp3RAOreojmdusw -228.6 188.8 MacBook Air
PaperCut Login fo… ALEKS Chemistry.. mistry — Oxygen OH” (aq) -157.2 H20 (1) -285.8 -237.1 70.0 H20 (9) -241.8 -228.6 188.8 02 (9) 0 205.2 H202 (1) -187.8 -120.4 109.6 H202 (9) – 136.3 -105.6 232.7 Phosphorus PA (s) 0 0 41. P4 (9) 58.9 24.4 280.0 PC13 (9) -287.0 -267.8 311.8 PC13 (1) -319.7 -272.3 217.1 PF5 (9) – 1594.4 -1520.7 300.8 PO3- (aq) 1018.7 H3PO4 (1) -1271.7 H3PO4(s) -1284.4 -1124.3 110.5 P4010 (5) -2984 +2675.2 228.9 sexews BBONTEKW 700mQKKK5yXavob FRIGRlboogtroFckCeD8 Va-XXVP3RAQOJ — MacBook Air
Answer
T = 25 + 273.15 = 289.15 K
R= gas constant = 0.0083145 KJ/mol.K
solution: 2 – Norgot clcg 2 Nocle) find AGayn: AGO – E A Gif (presducts) 1xn EAG ‘f(reactants) 2 x 66.1 kJ/ (2 2×87.6k] mol + (1xol *ok mo) mol 132-2 2 k) 175.2 KI mol mol 132.2 k 175.2 KI mol AG aan – -43 K] mol
We know that AG – AG + RT ln(2) – AG & RT ln – (PNoch)? (PNO )2 (BCI) AG 43 kJ mol + 0.0083145 kJ x 298.15k x malik (4.562 In (0-546) (148)
AG = (-43k] Mol 2.478968 175 KJ x.x x In (20.1936) mol.lt.0-298116.x 1.48 = – 43kJ +/2.478968175kJ.x ln/20.7936.mol 0.4412 1168 mo – – 43kJ+/2.478968175kJ.x in (47-1283987768.mol mal +(2.478968.175kJ.55655656 mol 9.551156405656 kJ.5511564056.5511564056.536256 mol.5511564056.
= -33.5kJ mol AG = 34 kJ (Ground to the nearest number) Mol Answer AG = -34 kJ
Conclusion
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